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2 years ago

What is the value of f(4) in f(x)=3x-6

Mathematics

1 answer:

vodka [1.7K]2 years ago

3 0

F(4) value is 6.
I believe it would work like this:
f(x) is being turned into f(4), so 4 would equal x. Put 4 into the equation 3x-6, and you get 12-6, which gives you 6. So the value of f(4) is 6. I hope this helps!

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Three dice are rolled. Let the random variable x represent the sum of the 3 dice. By assuming that each of the 63 possible outco

tamaranim1 [39]

<h3>Answer: 1/8</h3>

In decimal form, 1/8 = 0.125 which converts to 12.5%

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Work Shown:

The 63 should be 6^3. There are 6 choices per slot, and 3 slots, so 6^3 = 216 different outcomes.

Here are all of the ways to add to 11 if we had 3 dice

sum = 1+4+6 = 11
sum = 1+5+5 = 11
sum = 1+6+4 = 11
sum = 2+3+6 = 11
sum = 2+4+5 = 11
sum = 2+5+4 = 11
sum = 2+6+3 = 11
sum = 3+2+6 = 11
sum = 3+3+5 = 11
sum = 3+4+4 = 11
sum = 3+5+3 = 11
sum = 3+6+2 = 11
sum = 4+1+6 = 11
sum = 4+2+5 = 11
sum = 4+3+4 = 11
sum = 4+4+3 = 11
sum = 4+5+2 = 11
sum = 4+6+1 = 11
sum = 5+1+5 = 11
sum = 5+2+4 = 11
sum = 5+3+3 = 11
sum = 5+4+2 = 11
sum = 5+5+1 = 11
sum = 6+1+4 = 11
sum = 6+2+3 = 11
sum = 6+3+2 = 11
sum = 6+4+1 = 11

There are 27 ways to add to 11 using 3 dice. This is out of 216 total outcomes of 3 dice being rolled.

So, 27/216 = (1*27)/(8*27) = 1/8 is the probability of getting 3 dice to add to 11.

7 0

2 years ago

PLEASE HELP ME WITH EMPIRICAL RULE!! ASAP!

Nat2105 [25]

Answer:

hahahahahahahahahahhahahahahhahahahahhahagagagaggagagagahhahahahahha

8 0

2 years ago

Can anyone help me figure this out? It’s not 75 x 0.20.. thank you :) I’ll give Brainly!!

cluponka [151]

Answer:

Step-by-step explanation:

Dividends are paid quarterly and it wants the annual amount, so you have to mulitply what you originally got by 4

75*.2*4=60

8 0

2 years ago

Read 2 more answers

PLEASE HELP ME TRYING TO MAKE HONOR ROLL PLASE HELP PLEASE

Helga [31]

Step-by-step explanation:

a+(a+60)=760

a=adult tickets

a+60=student tickets

a+a+60=2a+60

2a+60=760

-60 -60

2a=700

÷2. ÷2

a=350

350 adult tickets

6 0

2 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

2 years ago