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Angelina_Jolie [31]
3 years ago
6

Intain their own homeostasis?​

Chemistry
1 answer:
Klio2033 [76]3 years ago
4 0

Explanation:

In mammals, they maintain their own homeostasis by negative feedback loops within the organism. homeostasis is controlled by the nervous and endocrine systems.

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Match the salt with the acid and base used to form it in a neutralizing reaction.
nignag [31]
<h3><u>Answer;</u></h3>

K2SO4 - KOH and H2SO4

NaBr - NaOH and HBr

<h3><u>Explanation;</u></h3>
  • Salts are compounds that contain positively charged ions and negatively charged ions. That is; they consist of the positive ion of a base and the negative ion of an acid.
  • Salts may be produced when acids and bases are combined together in equal proportions, a process called neutralization.
  • During neutralization reactions an acid reacts with a base to form a salt and water as the only products.
4 0
3 years ago
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Convert 7.72 years into days.
Lelu [443]

Answer:2817.8

Explanation:multiply the value by 365

4 0
3 years ago
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what is the chemical reaction in which the exchange of electropositive and electronegative ions occurs in aqueous solution​
defon

Answer:

chemical reaction are the processes in which new substances with new properties of from are called as chemical reaction ex double displacement reaction

Explanation:

7 0
3 years ago
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. How many grams of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide? ____Cl
dlinn [17]

Answer: 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide.

Explanation:

The balanced chemical reaction is;

Cl_2+MgBr_2\rightarrow MgCl_2+Br_2

Cl_2 is the limiting reagent as it limits the formation of product and MgBr_2 is the excess reagent.

According to stoichiometry :

1 mole of Cl_2 produces = 1 mole of MgCl_2

Thus 2 moles of Cl_2 will produce=\frac{1}{1}\times 2=2moles  of MgCl_2

 Mass of MgCl_2=moles\times {\text {Molar mass}}=2moles\times 95g/mol=190g

Thus 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide

5 0
3 years ago
How many molecules are in 145.5 grams of Be(OH)2
Zanzabum

Answer:

2.04 x 10²⁴ molecules

Explanation:

Given parameters:

Mass of Be(OH)₂ = 145.5g

To calculate the number of molecules in this mass of Be(OH)₂ we follow the following steps:

>> Calculate the number of moles first using the formula below:

Number of moles = mass/molarmass

Since we have been given the mass, let us derive the molar mass of Be(OH)₂

Atomic mass of Be = 9g

O = 16g

H = 1g

Molar Mass = 9 + 2(16 + 1)

= 9 + 34

= 43g/mol

Number of moles = 145.5/43 = 3.38mol

>>> We know that a mole is the amount of substance that contains Avogadro’s number of particles. The particles can be atoms, molecules, particles etc. Therefore we use the expression below to determine the number of molecules in 3.38mol of Be(OH)₂:

Number of

molecules= number of moles x 6.02 x 10²³

Number of molecules= 3.38 x 6.02 x 10²³

= 20.37 x 10²³ molecules

= 2.04 x 10²⁴ molecules

3 0
3 years ago
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