Explanation:
here is the answer bae. Feel free to ask for more chem help
It would be a triple bond because they overlap orbitals to share three pairs of electrons
Answer:
Option D. Saturated alkane
Explanation:
To know which option is correct, it is important that we know what saturated and unsaturated compounds are in this context.
Saturated hydrocarbons are compounds which has only carbon to carbon single bonds (C–C) in its chain. A very good example of such compound is the Alkanes.
Unsaturated hydrocarbons are compounds which has either a carbon to carbon double bond (C=C) or a carbon to carbon triple bond (C≡C) in its chain. Examples of such compounds include alkenes and alkynes.
Now, let us answer the question given above bearing the meaning of saturated and unsaturated compounds in mind.
The compound given above contains only carbon to carbon (C–C) single bond.
Therefore, the compound is a saturated alkane.
The net ionic equation is shorter to use and already leaves out the electrons that transferred from the reducing agent to the oxidizing agent. Also, in some occasions the aqueous ions H+ and (or) OH- ions that help balance the net ionic charge are no longer shown in the net ionic equation.
You can split the process in two parts:
1) heating the liquid water from 10.1 °C to 25.0 °C , and
2) vaporization of liquid water at constant temperature of 25.0 °C.
For the first part, you use the formula ΔH = m*Cs*ΔT
ΔH = 30.1g * 4.18 j/(g°C)*(25.0°C - 10.1°C) = 1,874 J
For the second part, you use the formula ΔH = n*ΔHvap
Where n is the number of moles, which is calculated using the mass and the molar mass of the water:
n = mass / [molar mass] = 30.1 g / 18.0 g/mol = 1.67 mol
=> ΔH = 1.67 mol * 44,000 J / mol = 73,480 J
3) The enthalpy change of the process is the sum of both changes:
ΔH total = 1,874 J + 73,480 J = 75,354 J
Answer: 75,354 J
