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3 years ago

Write the chemical equation that represents the process of lattice energy for the case of nacl.

Chemistry

2 answers:

almond37 [142]3 years ago

8 0

The equation for the lattice energy of NaCl is as follows;

$\boxed{{\text{N}}{{\text{a}}^ + }\left(g\right)+{\text{C}}{{\text{l}}^ - }\left(g\right) \to {\text{NaCl}}\left(s\right)}$

Further Explanation:

Lattice energy:

It is the amount of energy that is released when ions are combined to form an ionic compound or the energy required to break the ionic compound into its constituent gaseous ions. It cannot be measured directly and is denoted by ${\mathbf{\Delta }}{{\mathbf{H}}_{{\mathbf{lattice}}}}$ . It can have positive as well as negative values.

Case I: Positive lattice energy

The value of lattice energy $(\Delta }}{{\text{H}}_{{\text{lattice}}}}} \right))$ comes out to be positive if the energy supplied to the system is more than that released during the reaction. In other words, ${\Delta }}{{\text{H}}_{{\text{lattice}}}}$ is positive in case of endothermic reactions.

Case II: Negative lattice energy

The value of lattice energy $(\Delta }}{{\text{H}}_{{\text{lattice}}}}} \right))$ comes out to be negative if the energy released by the system is more than the energy supplied during the reaction. In other words, ${{\Delta }}{{\text{H}}_{{\text{lattice}}}}$ is negative in case of exothermic reactions.

Lattice energy is used to determine the stability of ionic compounds. NaCl is an ionic compound formed by one ${\text{N}}{{\text{a}}^ + }$ ion and one ${\text{C}}{{\text{l}}^ - }$ ion. The value of its lattice energy $({\Delta }}{{\text{H}}_{{\text{lattice}}}}} \right))$ is -787 kJ/mol. A high negative value of lattice energy indicates that the formation of NaCl is highly favored.

The equation for the lattice energy of NaCl is as follows;

${\text{N}}{{\text{a}}^ + }\left(g\right)+{\text{C}}{{\text{l}}^ - }\left(g\right)\to {\text{NaCl}}\left(s\right)$

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: lattice energy, NaCl, Na+, Cl-, negative, positive, favored, -787 kJ/mol, required, released, stability, ionic compounds.

faust18 [17]3 years ago

4 0

Answer: $Na^+(g)+Cl^-(g)\rightarrow NaCl(s),\Delta H_{Lattice}=-786kJ/mol$

Explanation:

Lattice energy : It is defined energy released when ions combine together in a gaseous phase to form a compound. it is energy possessed by the crystal lattice of a compound. Denoted by symbol $\Delta H_{Lattice}$ .

$\Delta H_{Lattice}=positive$ , energy is absorbed while forming of the lattice

$\Delta H_{Lattice}=negative$ , energy is release while forming of the lattice

$Na^+(g)+Cl^-(g)\rightarrow NaCl(s),\Delta H_{Lattice}=-786kJ/mol$

One mole of sodium ion when combines with one mole chloride ion release 786 kJ of energy.

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Answer:

Highest energy will be equal to $9.6\times 10^{-13}J$

Explanation:

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3 years ago

What mass of powdered drink mix is needed to make a 0.5 M solution of 100 mL?

Maru [420]

Answer:

There is 17,114825 g of powdered drink mix needed

Explanation:

Step 1 : Calculate moles

As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L

Since the volume is 100mL, we have to convert the concentration,

⇒0.5 / 1 = x /0.1 ⇒ 0.5* 0.1 = x = 0.05 M

This means there is 0.05 mol per 100mL

Step 2 : calculate mass of the powdered drink

here we use the formula n (mole) = m(mass) / M (Molar mass)

⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.

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There is 17,114825 g of powdered drink mix needed

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3 years ago

Read 2 more answers

Calculate the molarity (M) of a 600 ml solution of 0.54 moles of H2SO4.

icang [17]

Molarity (concentration) can be calculated by the equation:
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Hope this helps!

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3 years ago

Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

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3 years ago

How does the arrangement of elements in periods relate to electron configuration

VashaNatasha [74]

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Both elements' valance electrons are present in the 1st shell

(This is just a small example to understand the concept because other periods are long but the first period is short that's why I gave the example of the first period)

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3 years ago