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harkovskaia [24]
3 years ago
11

A single atom found on the periodic table is know as an

Chemistry
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

Element

Explanation:

A chemical element is a substance that contains only one type of atom, which is the smallest particle of an element

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When a plant _____, roots grow and a seedling begins to grow?
dusya [7]

Answer:

stem

Explanation:

3 0
1 year ago
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What is the solution's freezing point: 15 g of CH4N2O (Molar mass = 60.055 g/mol) in 200. g of H2O? (Kf = 1.86 (°C·kg)/mol)
AURORKA [14]

Ok to answer this question we firsst need to fin the number of mol of Urea (CH4N2O). to do this we simply :

1 mol of urea =15/60.055 = 0.25mol

therefore 200g of water contain 0.25mol

the next step is to determine the malality of our solution in 200g of water, to do this we say:

200 g = 1Kg/1000g = 0.2kg

therefor 0.25mol/0.2Kg = 1.25mol/kg

and from the equation:

we know that i = 1

we are given Kf

b is the molality that we just calculated

therefore;

the solutions freezing point is -2.325°C

8 0
1 year ago
Classify each of the following chemical reactions.
natulia [17]
1. Synthesis or Combination reaction
2. Double replacement reaction
3. Single Replacement reaction
4. Decomposition reaction

Please mark as brainliest if this helped!
7 0
3 years ago
Read 2 more answers
Type of molecule is shown below?<br> H<br> O=C<br> H
ololo11 [35]

Answer:

Carbonyl

Explanation:

While the diagram is slightly unclear, the molecule most likely being shown is a carbonyl. A molecule is a carbonyl when there is a carbon double-bonded to an oxygen.

6 0
1 year ago
What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)
rewona [7]

Answer:

Ka = 4.04 \times 10^{-11}

Explanation:

Initial concentration of weak acid = 4.5 \times 10^{-4}\ M

pH = 6.87

pH = -log[H^+]

[H^+]=10^{-pH}

[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M

HA dissociated as:

HA \leftrightharpoons H^+ + A^{-}

(0.00045 - x)    x     x

[HA] at equilibrium = (0.00045 - x) M

x = 1.35 \times 10^{-7}\ M

Ka = \frac{[H^+][A^{-}]}{[HA]}

Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}

0.000000135 <<< 0.00045

Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}

5 0
3 years ago
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