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Levart [38]
4 years ago
5

Use the terms atom and element to explain what makes silver and gold different

Physics
1 answer:
RoseWind [281]4 years ago
3 0
An element is a substance made of many atoms of the same kind. Silver and gold are different elements, for the following reason:
- silver is an element whose atoms have atomic number 47 (i.e., an atom of silver contains 47 protons and 47 electrons)
<span>- gold is an element whose aroms have atomic number 79 (i.e., an atom of gold contains 79 protons and 79 electrons)</span>
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What is the difference between relative time and absolute time?
Rama09 [41]

Relative time is the physical subdivision of the rocks found in the Earth's geology and the time and order of events they represent. Absolute time is the measurement taken from the same rocks to determine the amount of time that has expired

Explanation:

7 0
3 years ago
Approximating the eye as a single thin lens 2.70 cmcm from the retina, find the focal length of the eye when it is focused on an
Lena [83]

Answer:

0.37 cm

Explanation:

The image is formed on the retina which is at a constant distance of 2.70 cm to the lens. Therefore, image distance = 2.70 cm.

The object is at a distant of 265 cm to the lens of the eye.

From lens formula,

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

where: f is the focal length, u is the object distance and v is the image distance.

Thus, u = 265.00 cm and v = 2.70 cm.

\frac{1}{f} = \frac{1}{265} + \frac{27}{10}

  = \frac{10+7155}{2650}

\frac{1}{f}  = \frac{7165}{2650}

⇒ f = \frac{2650}{7165}

      = 0.37

The focal length of the eye is 0.37 cm.

8 0
3 years ago
An acrobatic airplane performs a loop at an airshow. The centripetal acceleration the plane experiences is 14.7 m/s2.  If it tak
Ivahew [28]

Answer:

754.8 m

Explanation:

The centripetal acceleration is given by

a=\frac{v^2}{r}

where v is the speed of the airplane and r is the radius of the loop.

We can rewrite the speed of the airplane as the ratio between the length of the circumference (2 \pi r) and the time taken:

v=\frac{2 \pi r}{t}

Substituting in the formula of the acceleration, we have

a=\frac{(2 \pi)^2 r^2}{t^2 r}=\frac{(2 \pi)^2 r}{t^2}

Re-arranging the formula and putting the numbers of the problem into it, we can find the radius of the loop, r:

r=\frac{at^2}{(2 \pi)^2}=\frac{(14.7 m/s^2)(45.0 s)^2}{(2 \pi)^2}=754.8 m

4 0
3 years ago
Read 2 more answers
A 14 N force is applied for 0.33 seconds. Calculate the impulse.
Marysya12 [62]
The impulse is 4.62 yea buddy
5 0
3 years ago
Hello, I just wanted to ask someone to correct my work and to check if everything is correct. Thank you!
IrinaVladis [17]

it look like everyting its correct


6 0
3 years ago
Read 2 more answers
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