Answer:
From the information provided we have:
PD ≅ RD (= 11)
∠CPD ≅ ∠CRD (= 90°)
They both have CD as the hypotenuse.
=> ΔCPD ≅ ΔCRD
=> ∠PCD ≅ ∠RCD
Now we know that:
∠RCP = ∠PCD + ∠RCD
∠RCP = 2 · ∠RCD
∠RCP = 2 · 33° = 66°
So the answer is B
Answer:
Think of it as a small number and a large number. If the large number is being divided by a small number, of course that would be larger than the small number being divided by the large number.
SOLUTION
From the question, we want to find the probability of selecting a slip of paper with the letter t on it, then selecting the letter r, with replacement.
This means the probability of selecting t and r.
That is

There are 12 letters (total outcomes). And there are 2r and 2t.
So probability becomes

Hence the answer is
Answer:
c = 32/3
Step-by-step explanation:
Eliminate the fraction by mult. all terms by 8: 96 + 3c = 64.
Subtract 64 from both sides, obtaining: 3c = 32. Solving for c, c = 32/3.
Answer:
10
Step-by-step explanation:
let the number be n then half the number is
n , so
n + 69 = 74 ( subtract 69 from both sides )
n = 5 ( multiply both sides by 2 to clear the fraction )
n = 10
Thus the number is 10