Answer:
dihdvsjhvbsuhdsvubhjvdhbdsvhbdsvhbkvdshbds
Step-by-step explanation:
DJ CUCRACH AAE SLAHTI8AOS
This sequence starts with an initial set; let’s call it s1. This set contains 20 cans, and every set following would have two less cans than the last set. So,
s1=20
s2=s1-2=18
s3=s2-2=16
•
•
•
s9=s8-2=4
How many cans in the display represents the value of each set added together, so we can denote this as
s1+s2+s3+...+s9
and replacing with values:
20+18+16+...+4 = 108
The number of cans in the display equals 108.
(The set notation seems weird, but by practicing this application now, the Calculus version will seem easier.)
USE PEMDAS ( parenthesis, exponents, multiplication, division, addition, subtraction)
[(1+5)⋅2−5]⋅2
[6⋅2−5]⋅2
[12−5]⋅2
7⋅2
14
The answer is: 14
W +Y =5000
20/100 x W= 30/100 X Y
W/5=3Y/10
10W=15Y
W=15Y/10=3Y/2
3Y/2+Y=5000
3Y+2Y=10,000
5Y=10,000
Y=2000
AND HENCE W=3 x2000/2=3000