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antiseptic1488 [7]
4 years ago
15

A. The boat uses a heat engine to move. This is a simple schematic of how a heat engine operates. Describe what this schematic i

s showing in terms of the laws of thermodynamics. (6 points)
Physics
1 answer:
Bond [772]4 years ago
5 0

Answer: The internal heat energy of the boat heat engine, metamorphoses into mechanical workdone that causes the boat to move.

Explanation: First law of thermodynamics tells us that energy cannot be created nor destroyed, it can only be transformed from one form to another.

The internal heat energy of the boat heat engine, metamorphoses into mechanical workdone that causes the boat to move.

According to the second law of thermodynamics which state that when energy changes from one form to another form, or matter moves freely, entropy (disorder) in a closed system increases. Differences in temperature, pressure, and density tend to even out horizontally after a while

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(this is somehow part of my science unit, dont ask why)
nirvana33 [79]

Answer:

 Height of coffee mug = 5 cm

Explanation:

  Changing all the data given in to unit cm

              50 mm = 5 cm

              20 cm  = 20 cm

              8 m    = 800 cm

              0.1 km = 100 m = 10000 cm

Since we need to find the height of coffee mug, it's height will not be more than 10 cm.

  So 5 cm is the correct choice.

6 0
4 years ago
A 75.0 W bulb is connected to a
adoni [48]

Answer:

Explanation:

W = 75 watts

V = 110 volts

Formula

W = V * I

Solution

75 = 110 * I          Divide by 110

75 / 110 = I

I = 0.6818 Amperes

6 0
3 years ago
When a 5 kilogram mass is
salantis [7]

Answer:If a 5-kilogram mass is raised vertically 2 meters from the surface of the Earth, its gain in potential energy is approximately 1) 0 J 2) 10 J 3) 20 J 4) 100 J 43.

Explanation:

7 0
3 years ago
The horizontal bar rises at a constant rate of three hundred mm/s causing peg P to ride in the quarter circular slot. When coord
SVETLANKA909090 [29]

Answer:

Explanation:

Given

Horizontal bar rises with 300 mm/s

Let us take the horizontal component of P be

P_x=rcos\theta

P_y=rsin\theta

where \thetais angle made by horizontal bar with x axis

Velocity at y=150 mm

150=300sin\theta

thus \theta =30^{\circ}

position ofP_x=rcos\theta =300\cdot cos30=300\times \frac{\sqrt{3}}{2}

P_x=259.80 mm

P=259.80\hat{i}+150\hat{j}

Velocity at this instant

u_x=-rsin\theta =300\times sin30=-150 mm/s

u_y=rcos\theta =300\times cos30=259.80 mm/s

4 0
3 years ago
A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases
Mila [183]

Answer:

Rise in level of fluid is 0.11 m

Rise in level of fluid in case of mercury is 0.728 cm or 7.28 mm

Solution:

As per the question:

Density of oil, \rho_{o} = 0.900\ g/cm^{3} = 900\ kg/m^{3}

Change in Pressure in the tank, \Delta P = 7.28\ mmHg

Density of the mercury, \rho_{m} = 13.6\ g/cm^{3} = 13600\ kg/m^{3}

Now,

To calculate the rise in the level of fluid inside the manometer:

We know that:

1 mmHg = 133.332 Pa

Thus

\Delta P = 7.28\ times 133.332 = 970.656\ Pa

Also,

\Delta P = \rho_{o} gh

where

g = acceleration due to gravity

h = height of the fluid level

970.656 = 900\times 9.8\times h

h = 0.11 m

Now, if mercury is used:

\Delta P = \rho_{m} gh

970.656 = 13600\times 9.8\times h

h = 0.00728 m = 7.28 mm

3 0
4 years ago
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