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kompoz [17]
3 years ago
5

A go-cart and rider have a mass of 14 kg. If the cart accelerates at 6m/s^2 during a 40 m sprint in 100 seconds, how much power

did the cart do? MUST SHOW ALL WORK!!!!!!!!!
Physics
1 answer:
lara [203]3 years ago
3 0

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

F = 14*6\\F = 84 [N]

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

W = F*d

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

W = 84*40\\W = 3360 [J]

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

P=W/t\\

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

Now replacing:

P=3360/100\\P=33.6[W]

The power is given in watts

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A man is using a fishing rod to catch fish in figure 1.
ryzh [129]

Answer:

Explanation:

Remark

In general, these 3rd class levers are very inefficient. Because the force distance is smaller than the load distance, you need to pull upward with more force that the weight of the load. So whatever the load is, the force is going to be much greater.

The distances are always measured to the pivot unless you are asked something specific otherwise.

Givens

F = ?

weight = 6N

Force Distance = F*d = 0.5 m

Weight Distance =W*d1 = 2 m

Formula

F*Fd = W*Wd

Solution

F*0.5 = 6 * 2            Divide by 0.5

F = 12/0.5

F = 24 N upwards

5 0
2 years ago
A 2290 kg car traveling at 10.5 m/s collides with a 2780 kg car that is initially at rest at the stoplight. The cars stick toget
avanturin [10]

Answer:

0.41

Explanation:

given,

mass of the car, m = 2290 Kg

initial speed = 10.5 m/s

mass of another car, M = 2780 Kg

distance moved = 2.80 m

coefficient of friction = ?

conservation of energy

m u = (M + m) V

2290 x 10.5 = (2290 + 2780) V

V = 4.74 m/s

using equation of motion

v² = u² + 2 a s

4.74² = 2 x a x 2.8

a = 4.02 m/s²

now using equation

a = μ g

4.02 = μ x 9.8

μ = 0.41

7 0
3 years ago
Does anyone know the answer to all of these questions
Rasek [7]

Answer:

i don't understand the hw

5 0
3 years ago
An object with a mass of 1500 g (grams) accelerates 10.0 m/s2 when an
masya89 [10]

Answer:

15N

Explanation:

F=ma

m=1500g = 1.5kg

a=10m/s2

1.5×10=15 N

8 0
3 years ago
Read 2 more answers
Substances have more kinetic energy in the ______ state than in the ______ state.
USPshnik [31]
Liquids state than in the solid state because when it is solid the particals cant move as much than in the liquid state 
4 0
3 years ago
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