Question

A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N , and the horizontal component of the force is 4.5 N . At what angle (in degrees) above the horizontal is the force directed?

Answer 1

Answer: Thus, the force is directed 72.5° above the horizontal.

Explanation:

The magnitude of the force, F = 15 N

let this force be detected at angle θ from the horizontal, then horizontal component of force is: F cos θ

and vertical component is F sin θ

Horizontal component is given,

F cos θ = 4.5 N

⇒15 N cos θ = 4.5 N

⇒ cos θ = 0.3

⇒ θ = cos⁻¹ 0.3 = 72.5°

Answer 2

The force is directed at about 73° above the horizontal

Further explanation

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

$\large {\boxed {F = ma }$

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

Given:

F = 15 N

Fx = 4,5 N

Unknown:

θ = ?

Solution:

To solve this problem, we will use the basic principles of trigonometry.

$\cos \theta = \frac{ adjacent }{ hypotenuse }$

$\cos \theta = \frac{F_x}{F}$

$\cos \theta = \frac{4.5}{15}$

$\cos \theta = 0.3$

$\theta = \cos^{-1} 0.3$

$\theta \approx 73^o$

Conclusion:

The force is directed at about 73° above the horizontal.

For more details, it can be seen in the picture attached.

Learn more

• Impacts of Gravity : brainly.com/question/5330244
• Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
• The Acceleration Due To Gravity : brainly.com/question/4189441
• Newton's Law of Motion: brainly.com/question/10431582
• Example of Newton's Law: brainly.com/question/498822

Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant