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3 years ago

Sin C = .9513 find the measure of angle c to the nearest whole degree

Mathematics

1 answer:

BARSIC [14]3 years ago

6 0

Answer:

72º

Step-by-step explanation:

C = arcsin .9513

C = 72.045199929442813

C = 72º

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CAN SOMEONE HELP ME I HAVE A BIG TEST BUT I SUCK AT MATH

allsm [11]

Answer:

y = 8

Step-by-step explanation:

if you do -2 + -2 and add ten to it you get 8

5 0

3 years ago

Line segment YV of rectangle YVWX measures 24 units.

Anna [14]

Answer: 8√3

<u>Step-by-step explanation:</u>

ΔXVW is a 30°-60°-90° triangle. This special triangle has corresponding sides of lengths: b - b√3 - 2b. So,

VW = b

XW = b√3

XV = 2b

Since, YV = 24, then XW = 24 and we stated above that XW = b√3. So,

24 = b√3

$\frac{24}{\sqrt{3}} = \frac{b\sqrt{3}}{\sqrt{3}}$

$\frac{24}{\sqrt{3}}$ = b

$\frac{24}{\sqrt{3}}(\frac{\sqrt{3}}{\sqrt{3}})$ = b

$\frac{24\sqrt{3}}{3}$ = b

8√3 = b

We are looking for side YX which is congruent (equal) to VW and we stated above that VW = b, So, VW = 8√3

7 0

3 years ago

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

romanna [79]

Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

c) $\dfrac{3575}{12236}$

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : $11+13=24$

Total number of ways to structure a jury of six people from a group of 24 people :-

$^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596$

a) Number of ways of selecting a jury of all students :-

$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

$^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

3 0

3 years ago

Which of the following scenarios demonstrates sampling bias? (A) To estimate the ethnic background distribution of residents of

ankoles [38]

Answer:

Option C.

Step-by-step explanation:

Sampling bias is a problem during the initial data gathering step of a survey.

When the first step is wrong, then the survey cannot produce non biased results.

The problem occurs when the design of the study is wrong the data collection procedure is wrong.

So, here answer seems C, because the starting point is not selected at random in this survey.

(C) Jean wants to estimate the mean amount of money spent on clothes per week by mall shoppers. She collects data from every 10th person entering a clothing store at the mall.

6 0

3 years ago

Can someone help ASAP please? X

Tju [1.3M]

I think the answer 5 over 2

6 0

3 years ago