Q3. You throw a ball into the air, it reaches a certain height and then comes back to you.
1 answer:
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1. 12m/s and here’s how. The equation for calculating velocity of a wave is lambda x frequency. So 2m x 6Hz. Hz can be 1/s so the only unit of measurement we get is meters and seconds. So the answer will be 12m/s.
2. Frequency=2Hz period= 0.5 seconds
Equation for frequency is velocity/wavelength. 10m/s divides by 5m = 2Hz.
Equation for period is 1 / frequency. 1 divided by 2 = 0.5 seconds
3. The answer is the picture of you can’t read my hand writing comment and say “ I need the info about the wave because I can’t read your hand writing “ thank you and I hoped I helped
2. Frequency=2Hz period= 0.5 seconds
Equation for frequency is velocity/wavelength. 10m/s divides by 5m = 2Hz.
Equation for period is 1 / frequency. 1 divided by 2 = 0.5 seconds
3. The answer is the picture of you can’t read my hand writing comment and say “ I need the info about the wave because I can’t read your hand writing “ thank you and I hoped I helped
1.
Explanation:
We have:
voltage in the primary coil
voltage in the secondary coil
The efficiency of the transformer is 100%: this means that the power in the primary coil and in the secondary coil are equal
where I1 and I2 are the currents in the two coils. Re-arranging the equation, we find
which means that the current in the secondary coil is 14% of the value of the current in the primary coil.
2. 5.7 V
We can solve the problem by using the transformer equation:
where:
Np = 400 is the number of turns in the primary coil
Ns = 19 is the number of turns in the secondary coil
Vp = 120 V is the voltage in the primary coil
Vs = ? is the voltage in the secondary coil
Re-arranging the formula and substituting the numbers, we find:
Answer: f=150cm in water and f=60cm in air.
Explanation: Focal length is a measurement of how strong light is converged or diverged by a system. To find the variable, it can be used the formula:
= (nglass - ni)(
-
).
nglass is the index of refraction of the glass;
ni is the index of refraction of the medium you want, water in this case;
R1 is the curvature through which light enters the lens;
R2 is the curvature of the surface which it exits the lens;
Substituting and calculating for water (nwater = 1.3):
= (1.5 - 1.3)(
-
)
= 0.2(
)
f = = 150
For air (nair = 1):
= (1.5 - 1)(
-
)
f = = 60
In water, the focal length of the lens is f = 150cm.
In air, f = 60cm.