Gravitational potential energy definition in 8 words

A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum

s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle= $q=-2.74\times 10^{-6} C$

Kinetic energy of particle= $K_E=6.65\times 10^{-10} J$

Initial time= $t_1=6.36 s$

Final potential difference= $V_2=0.351 V$

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

$qV=K.E$

Using the formula

$2.74\times 10^{-6}V_1=6.65\times 10^{-10} J$

$V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V$

Initial voltage= $V_1=2.43\times 10^{-4} V$

$\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2$

Using the formula

$\frac{V_1}{V_2}=(\frac{6.36}{t})^2$

$\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}$

$t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}$

$t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}$

$t=241.7 s$

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0

3 years ago

Joshua programs a robotic arm to place a block in a box by following the sequence of commands in the table. a 2-column table wit

GarryVolchara [31]

Step 2 does the robotic arm do work on the block. Joshua programs a robotic arm to place a block in a box. a four-row, two-column table.

<h3>What is a robotic arm?</h3>

A robotic arm is a type of artificial arm that may be programmed to do tasks similar to those of a human arm.

The arm can be the sum of the mechanism or part of a larger robot. Joints connect the manipulator's linkages, allowing rotational or translational motion.

By following the directions in the table, Joshua programs a robotic arm to place a block in a box. a four-row, two-column table.

The items in the first column labeled step are 1, 2, 3, and 4. Grip block, elevate block 10 cm, hold for 20 seconds, release block are the items in the second column labeled command.

Step 2 does the robotic arm do work on the block.

Hence,step 2 is the correct answer.

To learn more about the robotic arm refer:

brainly.com/question/14768119

#SPJ1

6 0

2 years ago

The smaller the mass of an object, the _____ its inertia

givi [52]

Answer:

The inertia of an object does not change. The only time the inertia would change is when the object changes mass. ... The acceleration of an object depends on the mass of the object as well as the force exerted. This means that if the mass is smaller, the acceleration will be greater.

Explanation:

4 0

3 years ago

Read 2 more answers

A photoelectric effect experiment finds a stopping potential of 1.93 V when light of wavelength 200 nm is used to illuminate the

PSYCHO15rus [73]

a) zinc

The equation of the photoelectric effect is:

$E=\phi + K$ (1)

where

E is the energy of the incident light

$\phi$ is the work function

$K$ is the maximum kinetic energy of the emitted photoelectrons

Here the wavelength of the incident light is

$\lambda=200 nm = 2\cdot 10^{-7} m$

so the energy of the light is

$E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{2\cdot 10^{-7} m}=9.95\cdot 10^{-19} J$

Converting into electronvolts,

$E=\frac{9.95\cdot 10^{-19}}{1.6\cdot 10^{-19} J/eV}=6.22 eV$ (2)

The stopping potential is the potential needed to stop the photoelectrons with maximum kinetic energy: so, the electrical potential energy corresponding to the stopping potential (V=1.93 V) must be equal to the maximum kinetic energy of the photoelectrons,

$U=q V = K$

and since the charge of the electron is

1 q = 1 e

We have

$K=(1 e)(1.93 V)=1.93 eV$ (3)

Combining (1), (2) and (3), we find the work function of the material:

$\phi = E-K=6.22 eV-1.93 eV=4.29 eV$

So, the cathode is most likely made of zinc, which has a work function of 4.3 eV.

b) The stopping potential does not change

As we said in part A), the stopping potential is proportional to the maximum kinetic energy of the photoelectrons, K.

The intensity of light is proportional to the number of photons that hit the surface of the metal. However, the energy of these photons does not depend on the intensity, but only on the frequency of the light.

Therefore, the energy of the photons (E) does not change when the intensity of light is doubled. Also, the work function $\phi$ does not change: this means that the maximum kinetic energy of the photoelectrons, K, does not change, and so the stopping potential remains the same.

6 0

3 years ago

In the formula Q = m × c ×Δ T, which symbol represents specific heat? c m Q Δ T

Licemer1 [7]

Answer:

C is your answer.

Explanation:

5 0

3 years ago

Gravitational potential energy definition in 8 words​

Gravitational potential energy definition in 8 words