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Anuta_ua [19.1K]
3 years ago
5

a rectangular garden has a length of 20 yards and a width of 42 yards. A diagonal path runs from one end of the garden to the ot

her. How long is the diagonal path?

Mathematics
1 answer:
NARA [144]3 years ago
7 0
Hi there!

Since we have a right-angled triangle, we can use the Pythagorean Theorem to find our answer. The Pythagorean Theorem states the following:
{ a}^{2} + {b}^{2} = {c}^{2}

In this formula a and b represent the legs of the triangle and c represents the length of the hypotenuse.

Let's substitute our data from the question.
{42}^{2} + 20 {}^{2} = c {}^{2}

Square.
1764 + 400 = c {}^{2}

Add.
2164 = c {}^{2}

And finally take the root of both sides. We only need to use the positive solution, since the length of the hypotenuse can't be negative.
c = \sqrt{2164}

The answer is B.
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Answer:

4\frac{3}{4} or 4.75

Step-by-step explanation:

first we're going to convert the number into improper fractions.

7\frac{1}{2}= \frac{15}{2} and 2\frac{3}{4}= \frac{11}{4}

For subtracting it is suitable to adjust both fractions to an equal denominator, so we're going to multiply \frac{15}{2}x2, it'll equal the same number.

So now we have \frac{30}{4}-\frac{11}{4}, 30-11= 19.

\frac{19}4} simplified is, 4\frac{3}{4}.

As you can see I also added 4.75 as an answer, that's if the answer must be a decimal.

I hope this helps you!

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mamaluj [8]

BSE is square.

Let side be s

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Diagonal be d

\\ \tt\longmapsto s=\dfrac{d}{\sqrt{2}}

\\ \tt\longmapsto d=s\sqrt{2}

\\ \tt\longmapsto d=90\sqrt{2}

\\ \tt\longmapsto d=127ft

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Answer:

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Step-by-step explanation:

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