The distance between two points knowing theirs coordinates:
AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(5,-4) & B(-3,-1) Given
A(x₁,y₁) & B(x₂,y₂)
AB =√[(-3-5))²+(-1-(-4)²] =√(73) = 8.381 ≈ 5.44 units
Answer:
Each classmate received 1/16
Step-by-step explanation:
5/8= 0.625
0.625 ÷ 10 = 0.0625
= 1/16
Substitute 136.5 for y.




Compare this equation with 
a = 1, b = - 191, c = 8190
or
or

or

or

or

or

x = 126 or x = 65
Hence, the points on the curve are (65, 136.5) and (126, 136.5).
The width of the air space is the distance between these points.
Width = 
= 
= 126 - 65
= 61
Hence, width of the air space is 61m.
Answer:
h(-4) =101
Step-by-step explanation:
H(x) = 6x ^2 +5
We have to find when h=4, putting it into function
h(-4) = 6(-4) ^2 +5
h(-4) = 6(16) +5
h(-4) = 96 +5
h(-4) =101