He spends 30 to enter and 4 per ride
y = 4x + 30....with x being the number of rides and y being the total cost
Answer: x = 4
Step-by-step explanation: f(2) = 3(2)-1 = 5. Meaning x needs to be a value that makes g(x) = 5. You can set them up equal to each other 5 = 2x-3 and solve. You end up getting x = 4.
Answer:
The results don't make sense
Step-by-step explanation:
We can solve by means of a 2x2 system of equations, we have to:
"x" is the number of children's tickets
"y" is the number of adult tickets
Thus:
8 * x + 8.75 * y = 259
x + y = 35 => x = 35 - y
replacing we have:
8 * (35 - y) + 8.75 * y = 259
280 - 8 * y + 8.75 * y = 259
- 8 * y + 8.75 * y = 259 - 280
0.75 * y = -21
y = -21 / 0.75
y = -28
Thus:
x = 35 - (-28) = 63
With these results we notice that the problem has inconsistency, since the value of the tickets cannot be given a negative number, I recommend reviewing the problem, since the approach is correct.
There would be 8 ones, 4 fives, 12 tens, and 4 twenties. That together would be about $228
