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olganol [36]
3 years ago
6

a space shuttle is 50 miles above earth an astronaut on the shuttle sees the sun rise over earth. to the nearest mile, what is t

he distance from the astronaut to the horizon? (hint: earths radius is about 4,000 miles)
Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0
From the astronaut to the horizon is a tangent line to the curvature of the earth.  And from that point on the horizon to the center of the earth is at a right angle to the tangent and is equal to the radius of the earth...so we can say

cosα=r/(r+h) where r is the radius of the earth and h is the height above the surface of the earth...

α=arccos(r/(r+h))

now tanα=d/r where d is the distance from the astronaut to the point on the horizon so:

tan(arccos(r/(r+h))=d/r

d=rtan(arccos(r/(r+h)))  and using r≈4000 and h=50 we get:

d=4000tan(arccos(4000/(4050)))

d≈634.42mi

d≈634 mi (to nearest mile)
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The reading speed of second grade students in a large city is approximately normal, with a mean of 90 words per
kari74 [83]

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The probability that a random sample of 10 second grade students from     the city results in a mean  reading rate of more than 96 words per minute

P(x⁻>96) =0.0359

Step-by-step explanation:

<em>Explanation</em>:-

<em>Given sample size 'n' =10</em>

<em>mean of the Population = 90 words per minute</em>

<em>standard deviation of the Population =10 wpm </em>

<em>we will use formula</em>

<em>                            </em>Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }<em></em>

<em>Let X⁻  = 96</em>

                           Z = \frac{96-90 }{\frac{10}{\sqrt{10} } }

                          Z =  1.898

<em>The probability that a random sample of 10 second grade students from     the city results in a mean  reading rate of more than 96 words per minute</em>

<em></em>P(X^{-}>x^{-} ) = P(Z > z^{-} )<em></em>

<em>                    = 1- P( Z ≤z⁻)</em>

<em>                    = 1- P(Z<1.898)</em>

                   = 1-(0.5 +A(1.898)

                   = 0.5 - A(1.898)

                   = 0.5 -0.4641 (From Normal table)

                  = 0.0359

<u><em>Final answer</em></u>:-

The probability that a random sample of 10 second grade students from  

                = 0.0359

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3 years ago
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