Answer:
Step-by-step explanation:
n = 101 × 103 = 10,403
sum of digits = 8
Answer:
A. 0.22
B. 0.18
C. 0.25
D. 0.244
Step-by-step explanation:
S = {51 to 100} = 50
The sample space S contains values from 51 to 100 which is a total of 50 different values.
A.
Probability of A (lies between the values of 90 to 100 = 11).
11/50 = 0.22
B.
For a student to fail the course, his course has to be less than 60 = from 51 to 59. A total of 9 values.
9/50 = 0.18
C.
For student to get c, (70 to 79) a total of 10 values: 10/50 = 0.20
P(student did not get C) = 1-0.20 = 0.80
To get B, ( 80 to 89)
10/50 = 0.20
Probability that a student who is known not to have a c grade has a b grade = 0.20/0.80 = 0.25
D.
Probability of passing lies between 60 to 100 = 41 scores
41/50 = 0.82
Probability of student who passed having a B = 0.20/0.82 = 0.244
Step-by-step explanation:
Step-by-step explanation:
\begin{gathered} \frac{8x - 3}{3x} = 2 \\ 8x - 3 = 6x \\ 8x - 6x = 3 \\ 2x = 3 \\ x = \frac{3}{2} \end{gathered}
3x
8x−3
=2
8x−3=6x
8x−6x=3
2x=3
x=
2
3
Multiply negative 0.5 times negative 8
The answer is 4