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3 years ago

The temperature of a sample of matter is a measure of the ?

1 answer:

3 0

Answer: the average kinetic energy of the particles.


Jusitification:


Temperature and heat energy are closely related.


While heat is the kinetic energy of the particles of a substance which is transferred from a hotter substance to a cooler one, the temperature is a measure of the average kinetic energy of the particles in a substance.


The relatively high kinetic energy the particles of a warm substance is transferred to the cooler one by the motion (vibration or translation) of the atoms of molecules. The energy transferred is heat energy.

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Given the Vapour Density of a hydrocarbon is 150, what is it's molecular formula.

Anna35 [415]

Molecular formula = C4H10.

or

Simplest ratio
Empirical formula mass = 12 1 + 1 1+ 16 1 = 29.

Molecular mass = 2 vapour density. = 2 58. = 116.

Molecular formula mass = n Empirical formula mass.

Molecular formula = n Empirical formula.

= 4 (CHO)

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3 years ago

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4 years ago

How many moles are there in 140.2 g of Ca

olga nikolaevna [1]

Answer:

3.5

Explanation:

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3 years ago

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What is Proportional to the energy of electromagnetic wave

padilas [110]

Answer:

The frequency

Step-by-step explanation:

The formula for the energy of an electromagnetic wave is

E = hf Thus,

E ∝ f and

f ∝ E

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3 years ago

Using the following standard reduction potentials, Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Ni2+(aq) + 2 e- → Ni(s) E° = -0.23 V ca

lina2011 [118]

Answer: The above reaction is non-spontaneous.

Explanation:

For the given chemical reaction:

$Ni^{2+}(aq.)+2Fe^{2+}(aq.)\rightarrow 2Fe^{3+}(aq.)+Ni(s)$

Here, nickel is getting reduced because it is gaining electrons and iron is getting oxidized because it is loosing electrons.

We know that:

$E^o_{(Fe^{3+}/Fe^{2+})}=0.77V\\E^o_{(Ni^{2+}/Ni)}=-0.23V$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=-0.23-0.77=-1.0V$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

As, the standard electrode potential of the cell is coming out to be negative for the above cell. Thus, the standard Gibbs free energy change of the reaction will become positive making the reaction non-spontaneous.

Hence, the above reaction is non-spontaneous.

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3 years ago