Answer:
K remains the same;
Q < K;
The reaction must run in the forward direction to reestablish the equilibrium;
The concentration of
will decrease.
Explanation:
In this problem, we're adding an excess of a reactant, chlorine gas, to a system that is already at equilibrium. According to the principle of Le Chatelier, when a system at equilibrium is disturbed, the equilibrium shifts toward the side of the equilibrium that minimizes the disturbance.
Since we'll have an excess of chlorine, the system will try to reduce that excess by shifting the equilibrium to the right. Therefore, the reaction must run in the forward direction to reestablish the equilibrium.
The value of K remains the same, as it's only temperature-dependent, while the value of Q will be lower than K, that is, Q < K, as Q < K is the case when reaction proceeds to the right.
As a result, since
is also a reactant, its concentration will decrease.
The reflection from plane mirror is shown in the diagram.
<h3><u>Explanation</u>:</h3>
The mirror is a plane surface which can reflect light. The diagram attached shows the schematic representation of reflection that occurs in a plane mirror.
The laws of reflection states that the incident ray, reflected ray and the normal at the point of incidence lies at the same plane. Here we can also see that all are lying on a same plane.
The second law states that angle of incidence is equal to angle of reflection. Here we can also see that the i =r. It is applicable here too.