All categories

3 years ago

Can someone help me solve all the questions in number 1?

Mathematics

1 answer:

erik [133]3 years ago

8 0

Answer:

1 = 50⁰

2 = 130⁰

3 = 50⁰

4 = 85⁰

5 = 130⁰

6 = 50⁰

7 = 85⁰

8 = 45⁰

9 = 45⁰

10 = 135⁰

11 = 135⁰

12 = 45⁰

You might be interested in

Which of the following fractions is equal to a repeating decimal

kiruha [24]

Answer: There are no fractions listed, so I can't help you. 1/3 is a repeating though, if that helps anything. Otherwise, you could use a calculator and just find the decimal of the fraction.

4 0

3 years ago

Read 2 more answers

HELP MEEEE How do you add and subtract functions?

nata0808 [166]

Answer:

To add or subtract functions, just add or subtract the values at each point where it makes sense. If the functions are given by formulas, you can just add or subtract the formulas (it doesn't matter whether you plug in values before or after).

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Aleks04 [339]

Balance in account cannot be less than

7 0

3 years ago

Selma's class is making care packages to give to victims of a natural disaster. Selma packs one box in 5 minutes and has already

Monica [59]

66 more min. he used which could be 1 hour and 6 min.

7 0

3 years ago

Read 2 more answers

The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

5 0

3 years ago