The large triangle is an isosceles since both angles at the base each equal 42°.
In an isosceles triangle the altitude z is at the same time median , then it bisects the opposite side in the middle . So w = 120/2 = 60
Now let's calculate z:
tan 42° = (opposite side) / (adjacent side) = z/60
tan 42° = 0.9,
0.9 = z/60 and z = 54
Answer:
Area=190.091 cm^2
Step-by-step explanation:
Area = 1/2(Pi x r^2) one-half because it's a semi-circle
Area=1/2(3.14 x 11^2)
11^2=121 so, Area=1/2(3.14 x 121)
Area=1/2(379.94)
Area=189.97 cm^2
adjustment:
Area=1/2(3.142 x 11^2)
Area=1/2(3.142 x 121)
Area=1/2(380.182)
Area=190.091
Answer:
the 73rd term of the arithmetic sequence is -964.
Step-by-step explanation:
The common difference in this arithmetic sequence is 13. This is obtained by subtracting 28 from 41. The first term is a(1) = -28.
The arithmetic sequence formula is a(n) = a(1) + d(n - 1), where d is the common difference and -28 the first term.
Then, in this case, a(n) = -28 - 13(n - 1), and
a(73) = -28 - 13(73 - 1) = -964
Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
Answer: C
Step-by-step explanation: I hope this helps :)
