$\left|\begin{array}{c|c}$Powers of 2&Value\\2^{-5}&\frac{1}{32}\\\\2^{-4}&\frac{1}{16}\\\\2^{-3}&\frac{1}{8}\\\\2^{-2}&\frac{1}{4}\\\\ 2^{-1}&\frac{1}{2}\\\\2^{0}&1\end{array}\right|$

From the given table, we observe that the negative power of 2 reduces by 1 at each step.

$2^{-5}X2=2^{-4}\\2^{-4}X2=2^{-3}\\2^{-3}X2=2^{-2}$

Therefore, as the exponents increase, we multiply the previous value by 2 to obtain the next value.

The correct option is D.

6 0

3 years ago

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How do you multiply a mixed fraction by a regular fraction

Dmitriy789 [7]

Well, you first have to make the mixed fraction into an improper fraction. You then multiply the two fractions and ad the whole number into the total.

That's how i was taught back in the 4th grade... i'm not sure if it's correct but i hope it is-

3 0

3 years ago

X(2x-5)+x(2x-3)=(4x+6)(x-3)

Helga [31]

Answer:

x=9

Step-by-step explanation:

4 0

3 years ago

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Your paycheck from work was $304.25. You used some of your earnings to buy an MP3 player for $149. Now it will cost you $1.15 to