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Korvikt [17]
3 years ago
6

A bag contain 9 red tiles 3 yellow tile 6 blue tiles 11 green tiles and 7 purple tiles Max drew tiles 20 times the table shows t

he results for which colour the title is the experiments possibility closest the theoretical probability?

Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

The probability of drawing a red tile is 36% and the probability of not drawing a red tile is 64%.

Step-by-step explanation:

adoni [48]3 years ago
3 0

Answer:

Theoretically, green would be the most likely. Just theoretically speaking.

Step-by-step explanation:

You have approximately a 30 percent chance at green,

A 16 percent chance at blue,

A 25 percent chance at red,

A 19 percent chance of purple,

And a 8 percent chance at yellow.

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Find the volume of the tank below.<br> A. 63 m^3<br> B. 54 m^3<br> C. 78 m^3<br> D. 96 m^3
Andrei [34K]

Answer:

V = 62.832m^3 (Approximation to the nearest thousandth)

Step-by-step explanation:

The area of a cylinder can be determined by the formula:

V = \pi r^2h    (We know that the radius, r, is 2m, and the height, h, is 5m, so we can substitute them into the formula to calculate the volume of this cylindrical tank)

V = \pi * 2^2 * 5    (Simplify)

V = 20\pi

V = 62.832m^3 (Approximation to the nearest thousandth)

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What is the area of a field that is 132.4m long by 28m wide?
svetlana [45]

Answer:

B

Step-by-step explanation:

its 132.4 times 28

=3707.2

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3 years ago
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sladkih [1.3K]

2m+22


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Which of the following gives a valid reason for using the given solution method to solve the system of equations shown? Equation
alukav5142 [94]

Answer:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

Step-by-step explanation:

Equation I: 4x − 5y = 4

Equation II: 2x + 3y = 2

These equation can only be solved by Elimination method

Where to Eliminate x :

We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I

Hence:

Equation I: 4x − 5y = 4 × 2

Equation II: 2x + 3y = 2 × 4

8x - 10y = 20

8x +12y = 6

Therefore, the valid reason using the given solution method to solve the system of equations shown is:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

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3 years ago
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