Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
This gives no information, how many of each were sold
Answer:
number 2 is the answer or 4*pi inches² or 12.6
Step-by-step explanation:
Quadratic functions are second-order equations of the form y=ax^2+bx+c. Their graphs form parabolas. The defining characteristic of a quadratic is that the acceleration of the outputs is a constant.
Step-by-step explanation:
162/2 (the same as 162÷2) =83.5
83.5+83.5=162
^
that was two times to add so we know for sure that 162/2=83.5. Theres no special way to solve it since its just dived by <em>two</em>. Its just 162÷2=83.5
Hope this helps.