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3 years ago

The sum of 10 times a number and fifteen is added to 11 times the same number. (how do i make this into a algebraic expression?)

Mathematics

1 answer:

Ne4ueva [31]3 years ago

6 0

10a times (15+11) or 10a times 26

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Explain how to graph y = 3/4 x - 8

schepotkina [342]

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3 years ago

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dezoksy [38]

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2 years ago

Read 2 more answers

On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

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3 years ago

Plsssssss help me with thiss.

Oksanka [162]

Answer:

Step-by-step explanation:

you need to mutpliy all or your numders 17 x 4 x 8 x 9 = 4896m

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3 years ago

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