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vodka [1.7K]
3 years ago
10

Simplify all

Mathematics
2 answers:
musickatia [10]3 years ago
8 0
(2xy)2(3x^{2})(4y^{4})\\
(2*2*3*4)*(x*x^{2})*(y*y^{4})\\
48x^{3}y^{5}\\\\

3(2x)4(4x^{5}y)2\\
(3*2*4*4*2)*(x*x^{5})*y\\
192x^{6}y\\\\

(2n^{6}y^{5})(6n^{3}y^{2})(ny)3\\
(2*6*3)*(n^{6}*n^{3}*n)*(y^{5}*y^{2}*y)\\
36n^{10}y^{8}\\\\

(2a^{3}b^{2})(b^{3})2\\
(2*2)*a^{3}*(b^{2}*b^{3})\\
4a^{3}b^{5}
Law Incorporation [45]3 years ago
6 0
1:48x^4y^6
2:768x^14y^2
3:12n^12y^10
4:2a^3b^8
Hopefully I'm right
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Part of a hundredths grid is shown.
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The standard deviation of a sample taken from population A is 17.6 for a sample of 25.
lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation \sigma_A is

\sigma_A = 17.6

The sample size n_A is:

n_A = 25.

For the sample of population B, the standard deviation \sigma_B is

\sigma_B = 21.2

The sample size n_B is:

n_B = 30.

Then the standard deviation for the difference of means has the following form:

\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}

Finally

\sigma=\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}}\\\\\sigma= 5.23

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4 years ago
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A hot-air balloon is sighted at the same time by two friends who are 1.0 mile apart on the same side of the balloon. the angles
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Tan 25.5 = h/x

Tan 20.5 = h / x+1

x tan 25.5 = (x+1) tan 20.5

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0.476975532x = 0.373884679x + 0.373884679

Deduct both sides by .373884679

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Add one to get for the second person

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7/9-3/8
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