Solve This. (4x+12) (6x+2)

Mathematics

1 answer:

Mamont248 [21]2 years ago

6 0

The answer is 24x^2 + 80x + 24

You might be interested in

Please solve this fast late night homework session and I need to get as much done as possible...

aksik [14]

Answer:

-4

Step-by-step explanation:

4x+3y=-1

3x + y=-7

Solve for Y

3x+y=-7

-3x. -3x

y= -3x - 7

Plug in Y into the top equation

4x + 3 (-3x - 7) = -1

Distribute the Parenthesis

4x -9x-21=-1

Combine Like terms

-5x = 20

Divide by -5 on both sides

20/-5

x = -4

7 0

2 years ago

Circle the number sentence that has a mistake. Correct it to complete the related facts 7+ 9=16. 16+9=7. 9+7=16. 16-7=9

nasty-shy [4]

Answer:

16+9 does not equal 7.

It would be 16-9=7

8 0

3 years ago

HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x

Anna35 [415]

$\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0$

$\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}$