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Lady bird [3.3K]
4 years ago
11

At a certain location, wind is blowing steadily at 18 m/s. Determine the mechanical energy of air per unit mass and the power ge

neration potential of a wind turbine with 80-m-diameter blades at that location. Also, determine the actual electric power generation, assuming an overall efficiency of 30 percent. Take the air density to be 1.25 kg/m3.
Physics
1 answer:
777dan777 [17]4 years ago
5 0

Answer:

e_{mec}=162J/kg

P_{potential}=18312480W=18312.5kW

P_{actual}=5493.7kW

Explanation:

Given data

Diameter d=80m

Speed v=18 m/s

Efficiency n=30%

Air density p=1.25 kg/m³

For Mechanical energy of air per unit mass

The power potential of wind per unit mass could be defined as follow:

e_{mec}=\frac{v^2}{2}\\e_{mec}=\frac{(18m/s)^2}{2} \\e_{mec}=162J/kg

For  Power generation potential

The generation potential of turbine will determined from the available kinetic energy of air:

P_{potential}=e_{mec}m\\P_{potential}=e_{mec}pV\\P_{potential}=e_{mec}p\frac{dV}{dt}\\ P_{potential}=e_{mec}pA\frac{dx}{dt} \\P_{potential}=e_{mec}pr^2\pi v\\P_{potential}=(162J/kg)(1.25kg/m^3)(\frac{80m}{2} )^2\pi (18m/s)\\P_{potential}=18312480W=18312.5kW

For Actual power

The actual power generation could be defined as follow as:

P_{actual}=nP_{potential}\\P_{actual}=0.3*18312.5kW\\P_{actual}=5493.7kW  

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1. In an experiment, a positively charged oil droplet weighing 6.5 x 10-15 N is held stationary
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The charge on the droplet must be 1.2\cdot 10^{-18} C

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4.9\ m/sec^2

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data provided in the question

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Hence, the acceleration of the particle down the slope is 4.9 m/sec^2

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