Answer:
Inductance as calculated is 13.12 mH
Solution:
As per the question:
Length of the coil, l = 12 cm = 0.12 m
Diameter, d = 1.7 cm = 0.017 m
No. of turns, N = 235
Now,
Area of cross-section of the wire, A = 
We know that the inductance of the coil is given by the formula:
Answer:
1. <u>F = ma</u> <em>F = 0.2kg * 20m/s² = 4Kg * m/s² =</em> 4N
2. <u>F = ma</u> <em>F - 18Kg * 3m/s² = 54Kg * m/s² =</em> 54N
3. <u>F = ma</u> <em>F = 0.025Kg * 5m/s² =</em> 0.125N
4. <u>F = ma</u> <em>F = 50Kg * 4m/s² =</em> 200N
5. <u>F = ma</u> <em>F = 70Kg * 4m/s² =</em> 280N
6. <u>F = ma</u> <em>F = 9Kg * 9.8m/s² =</em> 88.2N
Explanation:
Hope this helps ! ^^
Answer:
52 rad
Explanation:
Using
Ф = ω't +1/2αt²................... Equation 1
Where Ф = angular displacement of the object, t = time, ω' = initial angular velocity, α = angular acceleration.
Since the object states from rest, ω' = 0 rad/s.
Therefore,
Ф = 1/2αt²................ Equation 2
make α the subject of the equation
α = 2Ф/t².................. Equation 3
Given: Ф = 13 rad, t = 2.5 s
Substitute into equation 3
α = 2(13)/2.5²
α = 26/2.5
α = 4.16 rad/s².
using equation 2,
Ф = 1/2αt²
Given: t = 5 s, α = 4.16 rad/s²
Substitute into equation 2
Ф = 1/2(4.16)(5²)
Ф = 52 rad.
