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Tatiana [17]
2 years ago
15

A massless string connects a 10.00 kg mass to a 13.00 kg cart which is resting on a frictionless horizontal surface. The mass ha

ngs over a frictionless pulley. When the mass is released, the cart accelerates to the right. What is the cart’s acceleration? The cart's acceleration is m/s^2. (round to one decimal place)
Physics
1 answer:
ch4aika [34]2 years ago
6 0

The cart's acceleration to the right after the mass is released  is determined as 7.54 m/s².

<h3>Acceleration of the cart</h3>

The acceleration of the cart is determined from the net force acting on the mass-cart system.

Upward force = Downward force

ma = mg

13a = 10(9.8)

13a = 98

a = 98/13

a = 7.54 m/s²

Thus, the cart's acceleration to the right after the mass is released  is determined as 7.54 m/s².

Learn more about acceleration here: brainly.com/question/14344386

#SPJ1

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The average reaction time is 1.5 seconds?<br><br> True<br> False
Umnica [9.8K]

Answer:

false

Explanation:

The average reaction time for humans is 0.25 seconds to a visual stimulus, 0.17 for an audio stimulus, and 0.15 seconds for a touch stimulus.

3 0
2 years ago
In a cloud chamber experiment, a proton enters a uniform 0.260 T magnetic field directed perpendicular to its motion. You measur
Sophie [7]

Answer:

the proton speed of the proton was 1.6 × 10⁶ m/s

Explanation:

Given the data in the question;

Radius r = 6.42 cm = 0.0642 m

magnetic field B = 0.260 T

we know that; charge of proton q = 1.602 × 10⁻¹⁹ C

And mass of proton m = 1.672 × 10⁻²⁷ kg

we know that; Magnetic Force F = qvBsinθ

where q is the charge of proton, v is velocity, B is the magnetic field and θ is  angle ( 90° )

Also the Centripetal force experienced by the particle is;

F = mv² / r

where r is radius, m is mass of proton and v is velocity

hence;

qvBsinθ = mv² / r

we solve for v

rqvBsinθ = mv²

divide both sides by mv

rqvBsinθ / mv = mv² / mv

rqBsinθ / m = v

so we substitute

v = [ 0.0642 m × (1.602 × 10⁻¹⁹ C) × 0.260 T × sin(90°) ] /  1.67 × 10⁻²⁷ kg

v = 2.6740584 × 10⁻²¹ / 1.672 × 10⁻²⁷

v = 1.6 × 10⁶ m/s

Therefore, the proton speed of the proton was 1.6 × 10⁶ m/s

4 0
3 years ago
Ball's velocity be in a year? Assume there are no nearby planets.
romanna [79]

Answer:

South

Explanation:

newton's third law explains for every action there is an equal and opposite reaction. the action is dropping the beanbag but because he is moving forward and gravity is pulling it down, the momentum is transferred to the beanbag and its reaction is to move south. North would be if he threw it.

5 0
3 years ago
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket
NARA [144]

The constant acceleration of a rocket launched upward, calculated knowing that the time it takes for a bolt that falls off the side of the rocker was 6.30 seconds, is 5.68 m/s².                                                                                      

When the rocket is launched straight up with constant acceleration, the acceleration of the rocket is given by:

v_{f_{r}} = v_{i_{r}} + at    

Where:                                                              

v_{f_{r}}: is the final velocity of the rocket

v_{i_{r}}: is the initial velocity of the rocket = 0

a: is the acceleration

t: is the time

After 4 seconds, the <u>final speed of the rocket</u> will be the <u>initial speed of the bolt</u>, so:                                              

v_{f_{r}} = v_{i_{b}} = at = 4a  

When the bolt falls off the side of the rocket, the bolt hits the ground 6.30 seconds later.        

The<u> initial height of the bolt</u> will be the <u>final height of the rocket</u>, and vice-versa. With this, we can take the final height of the bolt as zero.                        

y_{f_{b}} = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}

0 = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}

y_{i_{b}} = \frac{1}{2}9.81*(6.30)^{2} - 4a*6.30 = 194.7 - 25.2a

Now, as we said above, this height (of the bolt) will be the final height of the rocket, so:

y_{f_{r}} = y_{i_{r}} + v_{i_{r}}t - \frac{1}{2}gt^{2}

194.7 - 25.2a = 0 + 0 - \frac{1}{2}a(4)^{2}    

a = \frac{194.7}{33.2} = 5.86 m/s^{2}    

   

Therefore, the acceleration of the rocket is 5.68 m/s².

You can find another example of acceleration calculation here: brainly.com/question/24589208?referrer=searchResults

I hope it helps you!                                                                              

3 0
3 years ago
A mass of 25.5 g of H2O(g) at 373 K is mixed with 325 g of H2O(l) at 285 K and 1 atm. Calculate the final temperature of the sys
Vedmedyk [2.9K]

Answer:

331.28 K

Explanation:

To solve this problem, you need to know that the heat that the water at 373 K is equal to the heat that the water at 285 K gains.

First, we will asume that at the end of this process there won't be any water left in gaseous state.

The heat that the steam (H20(g)) loses is equal to the heat lost because the change of phase plus the heat lost because of the decrease in temperature:

Q_g = c_l*m_{wg} + m_{wg}*c*(T_{og}-T{fg})

The specific Heat c of water at 298K is 4.18 kJ/K*kg.

The latent heat cl of water is equal to  2257 kJ/kg.

The heat that the cold water gains is equal to heat necessary to increase its temperature to its final value:

Q_l = m_{wl}*c*(T_{fl}-T_{ol})

Remember that in equilibrium, the final temperature of both bodies of water will be equal.

Then:

Q_g = Q_l\\c_l*m_{wg} + m_{wg}*c*(T_{og}-T{fg}) = m_{wl}*c*(T_{fl}-T_{ol})\\2257 kJ/kg*0.0255 kg + 0.0255 kg*4.18 kJ/kg*K*(373K - T_f) = 0.325 kg*4.18kJ/kg*K*(T_f-285K)\\57.5535 kJ + 39.75807kJ - 0.10659T_f = 1.3585 T_f - 387.1725 kJ\\484.48407 kJ = 1.46244 T_f\\T_f = 484.48407 kJ /1.46244 = 331.28 K

4 0
4 years ago
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