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Tatiana [17]
2 years ago
15

A massless string connects a 10.00 kg mass to a 13.00 kg cart which is resting on a frictionless horizontal surface. The mass ha

ngs over a frictionless pulley. When the mass is released, the cart accelerates to the right. What is the cart’s acceleration? The cart's acceleration is m/s^2. (round to one decimal place)
Physics
1 answer:
ch4aika [34]2 years ago
6 0

The cart's acceleration to the right after the mass is released  is determined as 7.54 m/s².

<h3>Acceleration of the cart</h3>

The acceleration of the cart is determined from the net force acting on the mass-cart system.

Upward force = Downward force

ma = mg

13a = 10(9.8)

13a = 98

a = 98/13

a = 7.54 m/s²

Thus, the cart's acceleration to the right after the mass is released  is determined as 7.54 m/s².

Learn more about acceleration here: brainly.com/question/14344386

#SPJ1

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What is the potential energy of a 2 kg rock sitting at the top of a 10 meter high cliff?
prisoha [69]

Answer:200J

Explanation:E=MGH

= 2*10(assuming you round earth’s gravity to 10)*10

=200

8 0
3 years ago
Calculate the focal length of a lens needed by a woman whose near point is 50cm from her eyes, assuming the least distance of di
son4ous [18]

The focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.

To find the answer, we have to know about the focal length of correcting lens.

<h3>How to find the focal length of correcting lens?</h3>
  • If x is the distance of nearest point of the defective eye and D is the least distance of distinct vision, then, the expression for focal length of the correcting lens will be,

                           f=\frac{XD}{X-D}

  • It is given that, the woman whose near point is 50cm from her eyes, assuming the least distance of distinct vision for a normal eye is 25cm. Thus, the focal length will be,

                       f=\frac{50*25}{50-25} =50cm.

Thus, we can conclude that, the focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.

Learn more about the focal length here:

brainly.com/question/27915592

#SPJ9

4 0
2 years ago
a 1 gram spiders sits on a platform rotating at 78 rpm. the spider is 15 cm from the centre disk. find the speed of the spider
olga nikolaevna [1]

The spider is traveling in a circle with radius = 15cm

The circumference of any circle = <em>2 pi (radius)</em>
The circumference of the spider's path = 2 pi (15 cm) = 30 pi cm

The spider completes a trip around this path 78 times per minute.
Its speed, relative to you, is   

                               (78) x (30 pi) cm/min =

                                       2,340 pi cm/min =  7,351.33 cm/min =

                                     <em>  73.5133 meter/min =</em>

                                       <em>4.411 km/hr =</em>

                                         <em>2.74  miles/hour

</em>
(After the last appearance of pi,
all numbers are rounded.)<em>

</em>
8 0
4 years ago
Which form of energy does Theodore Roosevelt Lake have as the water collects in the
RSB [31]
C. because the energy is potential
7 0
3 years ago
In a drag race, a car takes off from rest and covers 375 meters in 5 seconds. What is the
salantis [7]

Explanation:

s = ut + 1/2 a t^2

375 = 0 * 5 + 1/2 * a * (5)^2

375 = 1/2 * a * 25

a = 375*2/25

a = 15* 2

a = 30m/sec^2

v = u + at

v = 0 + 30 * 5

v = 150 m/sec

hope it helps you

3 0
3 years ago
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