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alina1380 [7]
3 years ago
7

Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough s

o that the sample proportions follow a normal distribution?
Mathematics
1 answer:
Xelga [282]3 years ago
4 0

Answer:

Step-by-step explanation:

Complete Question:

Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough so that the sample proportions follow a normal distribution?

a) n=600 p=0.2

b) n=20, p=0.4

if np=10 and npq=10 then  the data follows normal distribution

a) np= 120,

q= 1-0.2= 0.8

npq= 600 ×0.2×0.4 = 48

Normal distribution is appropriate and sample size is large enough

b) np= 8

q= 1-0.4= 0.6

npq= 20 × 0.4×0.6= 4.8

sample size is not large enough so normal distribution is not appropriate.

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A weight suspended by a spring vibrates vertically according to the function D D given by D(t)=2sin(4π(t+18)) D ( t ) = 2 sin (
STALIN [3.7K]

Answer:

21.75 cm/s

Step-by-step explanation:

1 cm above central position means D = 1, so we plug in 1 into D(t) and find the time and which this occurs.

D(t)=2Sin (4\pi(t+18))\\1=2Sin (4\pi(t+18))\\\frac{1}{2}=Sin(4\pi t +72\pi)\\4\pi t + 72 \pi = \frac{\pi}{6}\\4\pi t = \frac{\pi}{6}-72\pi\\t=\frac{\frac{\pi}{6}-72\pi}{4\pi}

This is the time at which this occurs.

To find instantaneous rate of change, we differentiate D(t) and plug in this t we found. Remembering that d/dt (Sin t) = Cos t

D(t)=2Sin (4\pi(t+18))\\D(t)=2Sin(4\pi t + 72\pi)\\D'(t)=2Cos(4\pi t + 72\pi)(4\pi)

Now putting t:

D'(t)=2Cos(4\pi t + 72\pi)(4\pi)\\D'(\frac{\frac{\pi}{6}-72\pi}{4\pi})=2Cos(4\pi (\frac{\frac{\pi}{6}-72\pi}{4\pi}) + 72\pi)(4\pi)\\=8\pi Cos(\frac{\pi}{6})\\=21.75

Thus, the instantaneous rate would be around 21.75 cm/s

8 0
3 years ago
When a number is increased by 5% the result is 25 what is the original number to the nearest 10th
lbvjy [14]
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How many different 6 card hands of three face cards and three ace's can I choose from twelve face cards and four ace's?
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Answer:

The standard deviation of the sample mean is 4 minutes

Step-by-step explanation:

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

The standard deviation of the population is 32.

Sample of 64.

So

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