Answer:
greater
Explanation:
Let the initial velocity is u .
Acceleration due to gravity on earth, ge = g
Acceleration due to gravity on moon, gm = g / 6
Let the maximum height reached on earth is h and the maximum height reached on the moon is h'.
Use third equation of motion
At maximum height, the final velocity = 0.
For earth
0 = u^2 - 2 gh
h = u^2 / 2g ..... (1)
For moon
0 = u^2 - 2 g/6 x h'
h' = 6u^2 / 2g = 6 h (From (1)
So, the maximum height reached at moon is 6 times the maximum height reached at earth.
Answer:
6402.86 N
Explanation:
taking into account the energy-work theorem, we can write the following equation
Where F is the force, d is the distance, m is the mass, vf is the final velocity and vi is the initial velocity.
Solving for F, we get:
Replacing m = 830 kg, vf = 0 m/s, vi = 1.8 m/s, and d = 0.210 m, we get:
Therefore, the magnitude of the force is 6402.86 N
Answer:
The emf source acts as a charge pump, moving negative charges from the positive terminal to the negative terminal to maintain the potential difference. This increases the potential energy of the charges and, therefore, the electric potential of the charges.
Explanation:
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