Answer:
3.7kg
Explanation:
The following data were obtained from the question:
Volume = 3.7L
Mass =?
Next, we shall convert 3.7L to m³.
This is illustrated below:
1000L = 1m³
Therefore, 3.7L = 3.7/1000 = 0.0037m³
Now, we can obtain the mass of the water as shown below:
Density of water = 1000kg/m³
Volume of water = 0.0037m³
Mass of water =..?
Density = Mass /volume
1000kg/m³ = Mass /0.0037m³
Cross multiply
Mass = 1000Kg/m³ × 0.0037m³
Mass = 3.7Kg
Therefore, the mass of the water is 3.7Kg.
When the car comes to a stop, the final velocity must be 0 m/s.
Since the car js decelerating in a forward direction, acceleration must be negative.
final v = initial v + a•t
0 = 20 + (-6)t
t = 3.33s
Answer:
The angle that will have the most range (Goes further) <u>will be the one that is shot with 60 ° with the horizontal. </u>
Since the one that shoots with respect to the vertical, it will only reach higher. And it won't go as far as the horizontal.
Greetings.
Danna.
Answer:
The distance s of how far the ball will go at the highest setting = 2.25m
Explanation:
Let consider x to be the representative of the compression and the distance to be s
Recall that:
By cross multiplying
Thus, for the first setting
x = 1 , s = 0.25
for the second setting
x = 2, s = 1
1 = 0.25A + B --- (1)
4 = A + B ----- (2)
From (1); let B = 1 - 0.25A and substitute it into (2)
4 = A + 1 - 0.25 A
4 - 1 = A - 0.25 A
3 = 0.75 A
A = 3/0.75
A = 4
From (2)
4 = A + B
4 = 4 + B
B = 4 - 4
B = 0
Therefore, for the highest setting, where x = 3
Then :
will be:
3² = 4s + 0
9 = 4s
s = 9/4
s = 2.25 m
∴
The distance s of how far the ball will go at the highest setting = 2.25m
