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3 years ago

What happens when a star's core runs out of hydrogen and why does this occur?

Physics

2 answers:

UNO [17]3 years ago

7 0

Answer:

Explanation:

Sun is made up of gases mainly helium and hydrogen. The energy getting from sun is due to the fusion reaction between the hydrogen molecules in the sun. After a long time, when all the hydrogen is converted into helium, the fusion reaction stops, only very few hydrogen molecules fuse which are in the interior core of the sun.

The sun starts contracting due to the gravitational pull and the pressure the temperature increases. As the temperature reaches to a certain maximum value, the fusion of helium starts and then the sun again gives us energy in different forms.

Ad libitum [116K]3 years ago

5 0

When the core runs out of hydrogen to fuse, then it starts fusing the helium. This happens because a star cannot create more hydrogen.

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What do you mean by the statement relative density of gold is 19.3

sergey [27]

The relative density of gold is 19.3 it means the ratio obtained by dividing the density of gold by water at temp of 4 degree celcius is 19.3

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3 years ago

When gases, liquids, or solids are in contact with a moving object, the flow of _____ occurs due to frictional forces

mariarad [96]

When gases, fluids, or other solids are in contact with a moving object

heat is produced due to friction.

7 0

3 years ago

Read 2 more answers

When friction slows a sliding block___

Svetradugi [14.3K]

Answer:

Explanation:

When friction slows a sliding block, the kinetic energy of the block is transformed into internal energy .

The frictional movement of two surfaces over one another leads to the conversion of some of their kinetic energies to another energy - heat or thermal energy. Hence, the temperatures of the objects are raised in the process.

Therefore, when a sliding block is slowed down due to friction, some of the kinetic energy of the block would be transformed into internal energy in the form of heat.

The correct option is A.

6 0

2 years ago

You have to travel 5000 meters. You only have two minutes (120 seconds) to get there. How fast must you travel to get there in t

Sholpan [36]

Answer:

416.667 m/s

Explanation:

divide the distance by the time

8 0

3 years ago

A body of mass 2.7 kg makes an elastic collision with another body at rest and continues to move in the original direction but w

kramer

Answer:

1.35 kg

2.67 ms⁻¹

Explanation:

$m_{1}$ = mass of first body = 2.7 kg

$m_{2}$ = mass of second body = ?

$v_{1i}$ = initial velocity of the first body before collision = $v$

$v_{2i}$ = initial velocity of the second body before collision = 0 m/s

$v_{1f}$ = final velocity of the first body after collision =

using conservation of momentum equation

$m_{1} v_{1i} + m_{2} v_{2i} = m_{1} v_{1f} + m_{2} v_{2f}\\(2.7) v + m_{2} (0) = (2.7) (\frac{v}{3} ) + m_{2} v_{2f}\\(2.7) (\frac{2v}{3} ) = m_{2} v_{2f}\\v_{2f} = \frac{1.8v}{m_{2}}$

Using conservation of kinetic energy

$m_{1} v_{1i}^{2}+ m_{2} v_{2i}^{2} = m_{1} v_{1f}^{2} + m_{2} v_{2f}^{2} \\(2.7) v^{2} + m_{2} (0)^{2} = (2.7) (\frac{v}{3} )^{2} + m_{2} (\frac{1.8v}{m_{2}})^{2} \\(2.7) = (0.3) + \frac{3.24}{m_{2}}\\m_{2} = 1.35$

$m_{1}$ = mass of first body = 2.7 kg

$m_{2}$ = mass of second body = 1.35 kg

$v_{1i}$ = initial velocity of the first body before collision = 4 ms⁻¹

$v_{2i}$ = initial velocity of the second body before collision = 0 m/s

Speed of the center of mass of two-body system is given as

$v_{cm} = \frac{(m_{1} v_{1i} + m_{2} v_{2i})}{(m_{1} + m_{2})}\\v_{cm} = \frac{((2.7) (4) + (1.35) (0))}{(2.7 + 1.35)}\\\\v_{cm} = 2.67$ ms⁻¹

8 0

3 years ago