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kherson [118]
4 years ago
7

A circuit consists of a lightbulb, capacitor, battery, and open switch all in series. After the switch is closed, describe what

happens to the brightness of the lightbulb. Assume the capacitor is initially uncharged. The lightbulb has resistance so this is essentially an RC circuit.
Physics
1 answer:
Savatey [412]4 years ago
7 0

Answer:

Explanation:

Since this is an RC circuit, an RC circuit can be used to provide various time delays. The capacitor is connected in parallel across the lightbulb. WITH the battery connected , when the switch is closed , the capacitor voltage increases towards the battery voltage at a rate determined by the lightbulb resistance and the capacitance of the capacitor (called the time constant (τ)). The bulb will not emit any light and will act like an open circuit until the voltage across the capacitor reaches a certain level that can bright the bulb, when this voltage is reached the lightbulb brights gradually and the capacitor discharges through it, the lightbulb turns off again because the capacitor voltage drops fast and the capacitor recharges again and the lightbulb brights again

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Answer:

9.61 m

Explanation:

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The resultant displacement is given by

\overrightarrow{d}=\overrightarrow{d_{1}}+ \overrightarrow{d_{2}} +\overrightarrow{d_{3}}

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The magnitude of displacement is given by

d =

\sqrt{\left ( -0.707 \right )^{2}+\left ( 8.707 \right )^{2}+\left ( -4 \right )^{2}}

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3 years ago
What is the relationship between the valence electrons of an atom and the chemical bonds the atom can form?​
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Answer:

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Answer:

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