3 years ago

Tan 2θ; cos θ = 8 17 , θ in Quadrant I

1 answer:

5 0

The answer would be (20, 8) because it is in quadrant 1 and all numbers are posiive, so all you have to do is find wich one is the x codinate and wich one is y

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Stan, a local delivery driver is paid $3.50 per mile driven plus a daily amount of $75. On Monday he is assigned a route that is

Maurinko [17]

3.50m+75 for the 30 miles, he is being paid 105 plus the daily amount of 75 which equals to 180$.

4 0

3 years ago

A recent poll of 80 randomly selected Californians showed that 38% ( = 0.38) believe they are doing all that they can to conserv

Elanso [62]

The margin of error given the proportion can be found using the formula

$z* \sqrt{ \frac{p(1-p)}{n} }$

Where
$z*$ is the z-score of the confidence level
$p$ is the sample proportion
$n$ is the sample size

We have
$z*=2.58$
$p=0.38$
$n=80$

Plugging these values into the formula, we have:
$2.58 \sqrt{ \frac{0.38(1-0.38)}{80} } =0.14$

The result 0.14 as percentage is 14%

Margin error is 38% ⁺/₋ 14%

8 0

3 years ago

Read 2 more answers

-2(2x- _)+1=17-4x For what missing value is the equation an identity?

igor_vitrenko [27]

What’s grade are you?

4 0

3 years ago

TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$