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GarryVolchara [31]
3 years ago
5

Which letter has at least one line of symmetry? a.D b.J c.G d.L

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
The correct answer is A. D

That is because D has a horizontal line of symmetry, as can be seen on it.
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Find the number which exceeds 17319 by 1279
Andrei [34K]

Answer:

18598

Step-by-step explanation:

just add

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3 years ago
Solve the equation for the variable.<br><br><img src="https://tex.z-dn.net/?f=%20-%205v%20%2B%209%20%3D%20%20-%20v%20%2B%2017" i
AlekseyPX

Answer:

v= - 2

Step-by-step explanation:

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8 0
3 years ago
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
2 years ago
PLZ ANSWER THIS<br> thanksssss
just olya [345]

Answer:

It should be C) 11+ 3 5/8

Step-by-step explanation:

5 0
2 years ago
Dean ran 5 miles this week and wants to know how many kilometers he ran.
prisoha [69]

Answer:

8.04672 kilometers

1 mile = 1.06 km

5 miles = 8.04 ( or 8.04672)

4 0
3 years ago
Read 2 more answers
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