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ycow [4]
3 years ago
6

What is straight is part of a line and has 2 endpoints

Mathematics
1 answer:
Andrei [34K]3 years ago
4 0
A line segment has two endpoints and a ray has one endpoint....
so it is a line segment.
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A square is cut from a rectangle. The side length of the square is half of the unknown width w. The area of the shaded region is
Virty [35]

Answer:

  • See below

Step-by-step explanation:

<u>The side of the square is w/2, then its area is:</u>

  • A = (w/2)² = w²/4

<u>The shaded area is the difference of areas of the rectangle and the square:</u>

  • 14w - w²/4 = 84

<u>This can be simplified:</u>

  • 56w - w² = 336
  • w² - 56w + 336 = 0

8 0
3 years ago
Equation of a line into slope-intercept form, simplifying all<br> fractions.<br> 12x + 3y = -18
stellarik [79]

Answer:

y = -4x - 6

Step-by-step explanation:

12x + 3y = -18

Solve for y.

3y = -12x - 18

y = -12/3 x - 18/3

y = -4x - 6

3 0
3 years ago
Read 2 more answers
Es transversal por que puede separar zoos rectas y convertirse n perpendicular
Kamila [148]

Answer:

It is transversal because it can separate two lines and become n perpendicular

Step-by-step explanation:

7 0
3 years ago
Show both decimal places (5.06).
lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

<h3>How to find the cost of each call ?</h3>

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6)  \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9  \frac{1}{2} 2) = 1.66

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

#SPJ9

4 0
1 year ago
Mrs Hong had some milk. She used of it to bake some waffles and
Sergio [31]

<u><em>Answer:</em></u>

Mrs. Hong originally had 900 ml of milk

<u><em>Explanation:</em></u>

The complete question is in the attached image

Assume that the amount of milk Mrs. Hong originally had was x ml

<u>We are given that:</u>

1- She used \frac{1}{6} of it to bake the waffles, <u>therefore</u>:

   Amount used in baking waffles = \frac{1}{6}x ml

2- She used 300 ml to bake a pie

3- Amount left is half the original amount, <u>therefore</u>:

   Amount left = \frac{1}{2}x ml

<u>We know that:</u>

Total amount = amount used in waffles + amount used in pie + amount left

<u>Substitute with the givens and solve for x:</u>

Total amount = amount used in waffles + amount used in pie + amount left

x = \frac{1}{6}x + 300 + \frac{1}{2}x\\  \\x-\frac{1}{6}x-\frac{1}{2}x = 300\\   \\\frac{1}{3}x = 300\\  \\x = 300*3 = 900 ml

<u>This means that:</u>

She originally had 900 ml of milk

Hope this helps :)

7 0
3 years ago
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