4 years ago

What would you see at the wedding of Betty Crocker and the pillsbury dough boy

1 answer:

3 0

Cake
Biscuits
Sugar
Flour

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Savatey [412]

Answer: Point Form: ( 4 , 3 ) Equation Form: x = 4 , y = 3

Step-by-step explanation: Solve for the first variable in one of the equations, then substitute the result into the other equation.

Brainliest or a thank you please? :))

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3 years ago

Sonbull [250]

2564 rounded to the nearest ten

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3 years ago

Maru [420]

I believe the answer is A
but i’m not 100% sure

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3 years ago

amid [387]

This is not true.

$\tan^2x+\sec^2x=\dfrac{\sin^2x}{\cos^2x}+\dfrac1{\cos^2x}=\dfrac{1-\cos^2x+1}{\cos^2x}=2\sec^2x-1$

$2\sec^2x-1=1\implies\sec^2x=1\implies\sec x=\pm1\implies x=n\pi$

where is $n$ is any integer. So suppose we pick some value of $x$ other than these, say $x=\dfrac\pi4$ . Then

$\tan^2\dfrac\pi4+\sec^2\dfrac\pi4=1+2=3\neq1$

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3 years ago

netineya [11]

Answer:

answer

Step-by-step explanation:

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3 years ago