Explanation:
Let us assume that the separation of plate be equal to d and the area of plates is
. As the capacitance of capacitor is given as follows.
C = 
It is known that the dielectric strength of air is as follows.
E = 
Expression for maximum potential difference is that the capacitor can with stand is as follows.
dV = E × d
And, maximum charge that can be placed on the capacitor is as follows.
Q = CV
= 
= 
= 
= 
or, = 10.62 nC
Thus, we can conclude that charge on capacitor is 10.62 nC.
If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?
If the potential energy of the three-object system is to be a maximum (closest to zero), should object 3 be placed closer to object 1, closer to object 2, or halfway between them?
Object 3 should be placed closer to object 1.
Object 3 should be placed on a halfway between object 2 and object 1.
Object 3 should be placed closer to object 2.
Solution
I think that Object 3 should be placed closer to object 2.
Explanation:
The first attachment contains the complete question while the second attachment is the solution.
Answer:
is not this one Planet B is expected to be hotter than Planet A.
Explanation:
The initial speed of the automobile is 49.84km/hr
<u>Explanation:</u>
Given:
Acceleration, a = 1.77 m/s²
Time, t = 6s
Final speed, v = 88 km/h
v = 88 X 0.278 m/s
v = 24.464 m/s
Initial speed, u = ?
We know,
v = u + at
On substituting the value in the formula we get:
24.464 = u + (1.77 X 6)
24.464 = u + 10.62
u = 24.464 - 10.62 m/s
u = 13.844 m/s
Converting u = 13.844 m/s to km/hr
1 m/s = 3.6 km/hr
13.844 m/s = 13.844 X 3.6 km/hr
u = 49.84 km/hr
Therefore, the initial speed of the automobile is 49.84km/hr