Answer:
The west component of the given vector is - 42.548 meters.
Explanation:
We need to translate the sentence into a vectoral expression in rectangular form, which is defined as:

Where:
- Horizontal component of vector distance, measured in meters.
- Vertical component of vector distance, measured in meters.
Let suppose that east and north have positive signs, then we get the following expression:
![(x, y) = (-45\cdot \cos 19^{\circ}, -45\cdot \sin 19^{\circ})\,[m]](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-45%5Ccdot%20%5Ccos%2019%5E%7B%5Ccirc%7D%2C%20-45%5Ccdot%20%5Csin%2019%5E%7B%5Ccirc%7D%29%5C%2C%5Bm%5D)
![(x, y) = (-42.548,-14.651)\,[m]](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-42.548%2C-14.651%29%5C%2C%5Bm%5D)
The west component corresponds to the first component of the ordered pair. That is to say:

The west component of the given vector is - 42.548 meters.
Answer:
hello your question is incomplete attached below is missing part of the question
answer:
1 ) Magnetic field due to long current carrying wire : 
Therefore the net magnetic field due the both wires ; B = B
+ B
. when we adjust the current I
= I
then the Netfield (B ) = zero
2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires
3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

Explanation:
1 ) Magnetic field due to long current carrying wire : 
Therefore the net magnetic field due the both wires ; B = B
+ B
. when we adjust the current I
= I
then the Netfield (B ) = zero
2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires
3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

C. Electrical current increases as resistance decreases
Sam’s weight is 88.1 pounds
Answer:
B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)
Explanation:
Given
Outer diameter of the wire = b ⇒ R = b/2
Diameter of the clindrical hole at the center = a ⇒ r = a/2
The current that flows from left to right and is uniformly spread over the region between a and b = i
We apply Ampere's Law
Using the following formula for a/2 ≤ x ≤ b/2
B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)