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jekas [21]
3 years ago
6

The speed of sound through oxygen at 0°C is 316 meters per second. The speed of sound through solid copper is 5,010 meters per s

econd. Which of the following could be the speed of sound through liquid mercury? A. 52 meters per second B. 1,450 meters per second C. 6,130 meters per second D. 228 meters per second
Physics
2 answers:
vivado [14]3 years ago
5 0

Answer:

1,450 meters per second

Explanation:

Ray Of Light [21]3 years ago
3 0

Answer:1,450 meters per second

Explanation:

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What elements are in NaOH
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Answer: Sodim hydroxide have a formula of NaOH . So the elements present in the compound is sodium,oxygen and hydrogen.

Explanation:

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2 years ago
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When an electron falls from a higher to a lower energy level in an atom, the photon released has a wavelength of 121.6 nm. What
yarga [219]

Answer:

\Delta E=1.64*10^{-18}J

Explanation:

The energy difference between the energy levels involved in the transition of the electron is directly proportional to the frequency of the emitted photon:

\Delta E=h\nu(1)

Where h is the Planck constant. The photon's frequency is inversely proportional to its wavelegth:

\nu=\frac{c}{\lambda}(2)

Here c is the speed of light. Replacing (2) in (1):

\Delta E=\frac{hc}{\lambda}\\\Delta E=\frac{(6.63*10^{-34}J\cdot s)(3*10^8\frac{m}{s})}{121.6*10^{-9}m}\\\Delta E=1.64*10^{-18}J

6 0
2 years ago
________ is a measure of how many waves pass by in one second.
Sergio [31]
C. Frequency is a measure of how many waves pass by in one second.
4 0
3 years ago
A person of mass 70 kg stands at the center of a rotating merry-go-round platform of radius 2.9 m and moment of inertia 900 kg⋅m
Cloud [144]

Explanation:

It is given that,

Mass of person, m = 70 kg

Radius of merry go round, r = 2.9 m

The moment of inertia, I_1=900\ kg.m^2

Initial angular velocity of the platform, \omega=0.95\ rad/s

Part A,

Let \omega_2 is the angular velocity when the person reaches the edge. We need to find it. It can be calculated using the conservation of angular momentum as :

I_1\omega_1=I_2\omega_2

Here, I_2=I_1+mr^2

I_1\omega_1=(I_1+mr^2)\omega_2

900\times 0.95=(900+70\times (2.9)^2)\omega_2

Solving the above equation, we get the value as :

\omega_2=0.574\ rad/s

Part B,

The initial rotational kinetic energy is given by :

k_i=\dfrac{1}{2}I_1\omega_1^2

k_i=\dfrac{1}{2}\times 900\times (0.95)^2

k_i=406.12\ rad/s

The final rotational kinetic energy is given by :

k_f=\dfrac{1}{2}(I_1+mr^2)\omega_1^2

k_f=\dfrac{1}{2}\times (900+70\times (2.9)^2)(0.574)^2

k_f=245.24\ rad/s

Hence, this is the required solution.

5 0
2 years ago
Will give correct answer brainliest​
lukranit [14]

Answer:

I THINK it’s A

Explanation:

Because all the other answers don’t make sense.

5 0
2 years ago
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