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If a 2 x 10^-4C test charge is given 6.5J of energy, determine the electric potential difference.

Gwar [14]

Answer:

The electric potential difference is 32500 volt.

Explanation:

Given that,

Charge $q=2\times10^{-4}C$

Energy = 6.5 J

We need to calculate the electric potential difference

Potential difference :

Potential difference is equal to the energy divide by charge.

Using formula of potential difference

$V=\dfrac{E}{Q}$

$V=\dfrac{6.5}{2\times10^{-4}}$

$V=32500\ volt$

Hence, The electric potential difference is 32500 volt.

8 0

3 years ago

What does direction of force mean?

Gelneren [198K]

The direction of an arrow shows the direction of the force, and the length of the arrow indicates the amount, or size, of the force.

6 0

3 years ago

Insurance can help you

RUDIKE [14]

I dont know if insurance can help u sweeid

7 0

2 years ago

A 20 N force pulls to the right and friction pulls 5 N. If the mass is 5 kg, find acceleration.

Slav-nsk [51]

Answer:

Explanation:

Force - frictional Force = m * a

20N - 5N = 5 * a

15N = 5*a

15N / 5 = a

a = 3 m/s^2

You should note a couple of things.

1. The frictional Force always opposes the direction of motion. In this case it is minus and the 20 N is plus. It makes the acceleration less. If the friction force was not there then 20 N = m * a

20N = 5 kg * a

a = 20/5

a = 4 m/s^2.

7 0

2 years ago

Water drips from the nozzle of a shower onto the floor 193 cm below. The drops fall at regular (equal) intervals of time, the fi

Law Incorporation [45]

Answer: 108.81 cm and 48.66 cm

Explanation:

In this, we have to make sure to keep in mind the Gravity effects on the drops. The drops will accelerate when they fall making them travel faster. This means, the velocity is not constant.

What is know:

Height (h) = 193 cm

Gravity (g) = 981 $cm/s^{2}$

Initial Velocity = 0

First, we can know how long it take to the drop to travel to the floor. It can be done with the following equation:

$x = V_{0} t + \frac{1}{2} at^{2}$ (1)

Where:

x is the distance which is 193cm

Vo is the Initial Velocity which is zero

t is the time the time it takes the drop to travel from the shower to the floor

a is the aceleration, which in this case is the gravity.

With the Initial Velocity equals zero the equations simply:

$193 cm = \frac{1}{2}gt^{2}$

To search for the time:

$t =\sqrt{\frac{2*193cm}{981cm/s^{2} } }$

t = 0.627 s

This is the time it takes a drop to fall to the floor, with this time and knowing other 3 drops have driped from the shower by this time. We can calculate how much time it takes the shower to drip each drop.

Time for Drip = t/4

Time for Drip = 0.156

This time is the difference between each drop, using the same equation we can calculate where was each drop, because now it is know how much time had each drop after being drip from the shower.

Our first is already on the floor (193 cm) with 0.627 s, The second drops have been falling for (0.627s - 0.156) 0.471 s and our third drop for (0.627s - 0.156 - 0.156) 0.315 s

We can use (1) to know how far have each drop traveled on these times. We know the Initials Velocity are 0, know we need ot know the distances.

For the second drop:

$x = \frac{1}{2} (981cm/s^{2})(0.471s)^{2}$

$x =108.81 cm$

For the third drop:

$x = \frac{1}{2} (981cm/s^{2})(0.315s)^{2}$

$x = 48.66 cm$

8 0

2 years ago