A 75.0 kg students sits 1.15 m away from a 68.4 kg student. What is the force of gravitational attraction between them?
1 answer:
Answer:
F=2.589×10⁻⁷ Newtons
Explanation:
The gravitational force of attraction between two bodies is given by
F= Gm₁m₂/r²
Where m₁ and m₂ are the masses of the two bodies, G is the universal gravitational constant while r is the distance between the two bodies.
G=6.67408 × 10⁻¹¹m³kg⁻¹s⁻²
r=1.15m
m₁=75.0kg
m₂=68.4kg
Therefore F= (6.67408×10⁻¹¹m³kg⁻¹s⁻²×75.0kg×68.4kg)/(1.15m)²
F=2.589×10⁻⁷ Newtons
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