1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlexFokin [52]
3 years ago
6

What rights are specifically protected under the ninth amendment

Mathematics
2 answers:
AysviL [449]3 years ago
8 0
They protect peoples rights 
Nadya [2.5K]3 years ago
5 0
The ninth ammendment grants you freedoms not mentioned in laws
You might be interested in
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
4. Two friends, Sequoia and Raven, sold organic chap sticks at the local market.
Nina [5.8K]

Answer:

Sequoia sold 2 chap sticks while Raven sold 4.

Step-by-step explanation:

Since two friends, Sequoia and Raven, sold organic chap sticks at the local market, and Sequoia sold her chap sticks for $ 4 and Raven sold hers for $ 3 each, and in the first hour, their total combined sales were $ 20, if in the first hour, the friends sold a total of 6 chap sticks between them, to determine the number of chap sticks each of the friends sold during this time the following calculation must be performed:

6 x 4 + 0 x 3 = 24

5 x 4 + 1 x 3 = 23

2 x 4 + 4 x 3 = 20

Therefore, Sequoia sold 2 chap sticks while Raven sold 4.

7 0
3 years ago
More than one unknown in a word problem can be represented in terms of the same variable assigned to first unknown. true of fals
Sergeeva-Olga [200]
This is clearly false as it will just mess up the question.
6 0
3 years ago
Read 2 more answers
(101)² solve it using identities​
almond37 [142]

Answer:

10201

Step-by-step explanation:

=(101)²

=(100+1)²

={100²+2(100)(1)+1²} [(a+b)²=a²+2ab+b²]

=10000+200+1

=10201

7 0
3 years ago
The sum of two consecutive numbers is 77. The difference of half of the smaller number and one-third of
diamong [38]

Answer:

so x+y=77

1/2x-1/3y=6

6 0
3 years ago
Other questions:
  • VISUALIZATION Name the geometric term(s) modeled by each object.
    11·1 answer
  • Simplify the following expression.
    5·1 answer
  • What is the GCF of 10 and 12
    14·2 answers
  • Please answer this correctly
    15·1 answer
  • Find the missing number in the pattern below 14,21, ,35,42
    15·2 answers
  • The net of a triangular prism is shown.
    12·1 answer
  • Which two expressions have the same value?
    6·2 answers
  • Please help.<br> Algebra.
    12·1 answer
  • the north american plate and the pacific plate have been sliding horizontally past each other along the san andreas fault line f
    7·1 answer
  • 14) Chili's restaurant has 70 tables in the dining area. On a recent evening, there were reservations for 1/10 of the tables. Ho
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!