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AlexFokin [52]
3 years ago
6

What rights are specifically protected under the ninth amendment

Mathematics
2 answers:
AysviL [449]3 years ago
8 0
They protect peoples rights 
Nadya [2.5K]3 years ago
5 0
The ninth ammendment grants you freedoms not mentioned in laws
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What is the length of a missing side of a 48 feet and 52 feet 90° triangle
RideAnS [48]

Answer:

5

Step-by-step explanation:

5 0
3 years ago
What is the value of x?
BlackZzzverrR [31]
We can use the Pythagorean theorum

a^2+b^2=c^2

c^2 is the length of the longest side squared

so 

6^2 + b^2 = 10^2

36+ b^2 = 100
-36               -36

b^2 = 64

b = 8

b is the same thing as your "x", so x = 8
7 0
3 years ago
Read 2 more answers
(18 x 4) * 5 =<br> 22 x (6 x 10) =<br> 15 x (4 x 20) =
zhenek [66]

Answer:

(18 x 4) * 5 = 360

(18 x 4) * 5 = 1320

15 x (4 x 20) = 1200

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
4 years ago
Michelle ordered 200 T-shirts to sell at the school carnival. She paid $2.80 per shirt, plus 5% of the total order for shipping.
djyliett [7]

Answer: She should sell each T-Shirt for at least $4.41

Step-by-step explanation:

First you need to figure out what the total cost of the 200 t shirts was plus shipping. so 200 t shirts for 2.8 would cost $560 + a 5% shipping fee ($28) = 588 if she wants to markup by 150. you would then multiply 588 * 1.5 = $882. This would be the final money she wants to make by the end of her school carnival. Divide 882/200 (amnt of t-shirts) to get $4.41 per shirt

4 0
3 years ago
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