Find the Roots (Zeros) f(x)=x^3-6x^2+13x-20. f(x)=x3−6x2+13x−20 f ( x ) = x 3 - 6 x 2 + 13 x - 20. Set x3−6x2+13x−20 x 3 - 6 x 2 + 13 x - 20 equal to 0 0 .

Step-by-step explanation:

hope this helps

4 0

3 years ago

Help I’m almost out of time

VladimirAG [237]

Answer: First option.

Step-by-step explanation:

You can idenfity in the figure that $\angle FCE$ is formed by two secants that intersect outside of the given circle.

It is important to remember that, by definition:

$Angle\ formed\ by\ two\ Secants=\frac{1}{2}( Difference\ of\ intercepted\ Arcs)$

Knowing this, you can set up the following equation:

$m\angle FCE=\frac{1}{2}(BD-FE)$

Therefore, you must substitute values into the equation and then evaluate, in order to find the measure of the angle $\angle FCE$ .

This is:

$m\angle FCE=\frac{1}{2}(112\°-38\°)\\\\m\angle FCE=37\°$

6 0

3 years ago

What is the equation of the line passing through the points (4, -7.5) and (6, -3.5) in slope-intercept form?

Ratling [72]

Answer:

Your answer will be

y=2x-15.5

Step-by-step explanation:

Hi, there you must know the slope-intercept form which is

y=mx+b

m=slope

b=y-intercept

You can also use

the slope formula which is

$\frac{y_2-y_1}{x_2-x_1}$

in this case

it will look like this

$\frac{-7.5-(-3.5)}{6-4}$ = $\frac{-4}{2}$ =-2

So the slope is -2

Now we will find the y-intercept

-7.5=2(4)+b

-7.5=8+b Subtract 8 both sides

-15.5=b

Your y-intercept is -15.5

Hope this helps

6 0

3 years ago