The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Answer:
Bro your so fing pretty
Step-by-step explanation:
Answer: $15.00 per person.
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Explanation:
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Given that there are "4 people" (that is, "Kianna and three friends");
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and a total of "$58.49" ; to be divided equally among 4 (four) people;
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we are asked to <em><u>estimate</u></em> the amount that EACH person will pay.
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For an <em><u>ESTIMATE</u></em>, $58.49 is ABOUT $60.00; or "60 dollars". ;
and (60 dollars) / 4 = 15 dollars {$15; or $15.00}.
60/4 = 15; or 60/4 = (60÷2)/(4÷2) = 30/2 = 15.
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The simplified expressions are 2^-2 and 60^6
<h3>How to simplify the expressions?</h3>
<u>Expression (a)</u>
We have:
2^3 * 2^-5
Apply the product law of indices
2^3 * 2^-5 = 2^(3 - 5)
Evaluate the difference
2^3 * 2^-5 = 2^-2
<u>Expression (b)</u>
We have:
(60^2)^3
Apply the power law of indices
(60^2)^3 = 60^(2 * 3)
Evaluate the product
(60^2)^3 = 60^6
Hence, the simplified expressions are 2^-2 and 60^6
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