Answer:
a. L² = 3L(L - 10)
b. The equation could be used to determine the length of a side of the original sandbox since, the areas of both sandboxes are the same.
c. 225 m²
Step-by-step explanation:
a. Let L represent the length of side of the original square sandbox. Since one side of the new rectangular sandbox is increased by 3, so we have one side as 3L and the other side reduced by 10 meters, we have the other side as L - 10.
The area of the original square sandbox = L²
The area of the new rectangular sandbox = 3L(L - 10).
Since both areas are the same, we equate them.
So, L² = 3L(L - 10)
b. L² = 3L(L - 10)
The above equation could be used to determine the length of a side of the original sandbox since, the areas of both sandboxes are the same.
c. We find the area of the new rectangular garden by first solving the equation to find the length of the original sandbox.
So, L² = 3L(L - 10)
Expanding the brackets
L² = 3L² - 30L
Collecting like terms
3L² - L² = 30L
2L² = 30L
2L² - 30L = 0
2L(L - 15) = 0
2L = 0 or L - 15 = 0
L = 0 or L = 15
Since L ≠ 0 we choose L = 15 meters
So the area of the rectangular sandbox = 3L(L - 10) = 3(15)(15 -10) = 45 × 5 = 225 m²
Divide both sides by 7 to get the variable, x on its own:
X = 28/7
x = 4
Hope this helps you,
Have a great day
Answer:
<h2>245,600,000,000</h2>
Step-by-step explanation:
245 Billion, 600 Million, Thousand, Hundreds
Hope this helps! <3
39 + 0.16m = 25 + 0.24m
39 - 25 = 0.24m - 0.16m
14 = 0.08m
14 / 0.08 = m
175 = m <=== they will cost the same at 175 miles
39 + 0.16(175) = 39 + 28 = $ 67
25 + 0.24(175) = 25 + 42 = $ 67
they will both cost $ 67 <=====
Answer: A B
Group A 0.25 0.75
Group B 0.45 0.55
Step-by-step explanation:
Since we have given that
Number of people of A in Group A = 15
Number of people of B in Group A = 45
Number of people of A in Group B = 20
Number of people of B in Group B = 25
Total number of people in Group A = 15+45 = 60
Total number of people in Group B = 20+25 = 45
So, Relative frequencies will be given below:
Relative frequency of A in Group A is given by
Relative frequency of B in Group A is given by
Relative frequency of A in Group B is given by
Relative frequency of B in Group B is given by
Hence, A B
Group A 0.25 0.75
Group B 0.45 0.55
