Answer:
Standard deviation = 14.064
Step-by-step explanation:
We are given the following data;
X X - 
20 20 - 46 = -26 676
23 23 - 46 = - 23 529
32 32 - 46 = -14 196
36 36 - 46 = -10 100
41 41 - 46 = -5 25
43 43 - 46 = -3 9
44 44 - 46 = -2 4
45 45 - 46 = -1 1
47 47 - 46 = 1 1
54 54 - 46 = 8 64
55 55 - 46 = 9 81
59 59 - 46 = 13 169
61 61 - 46 = 15 225
63 63 - 46 = 17 289
66 66 - 46 = 20 <u> 400 </u>
<u>= 2769 </u>
Firstly we will calculate Mean, = 
= 45.93 ≈ 46
Now, Standard deviation formula is given by;
s = 
= 
= 14.064 .
So remember that percent means parts out of 100
60%=60/100=6/10
so every 10 throws she makes 6
how many 5 in 50?
50/10=5
answe ris 5
so 5 tens so therefor 5 sixes
5 times 6=30
answer is 30 throws
Answer: The graph in the bottom right-hand corner
(see figure 4 in the attached images below)
===========================================
Explanation:
Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.
Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.
After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.
