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2 years ago

What do you call when a relation with each x value has one y value

Mathematics

1 answer:

Nitella [24]2 years ago

5 0

When each x value has only one y value, the relation is a function

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Solve the measure of an angle is 161°. what is the measure of a supplementary angle?

lions [1.4K]

Supplementary angles sum up to 180°, suppose the supplement of 161° is x. Then
161+x=180
solving for x we subtract 161 from both sides
161-161+x=180-161
x=19
thus the supplement is 19°

4 0

3 years ago

What value of x makes the following equation true? 15+3x=3(2−2x)

Alinara [238K]

Answer:

$\boxed {x = -1}$

Step-by-step explanation:

Solve for the value of $x$ :

$15 + 3x = 3(2 - 2x)$

-Use Distributive Property:

$15 + 3x = 3(2 - 2x)$

$15 + 3x = 6 - 6x$

-Take $6x$ and add it to $3x$ :

$15 + 3x + 6x = 6 + 6x - 6x$

$15 + 9x = 6$

-Subtract both sides by $15$ :

$15 - 15 + 9x = 6 - 15$

$9x = -9$

-Divide both sides by $9$ :

$\frac{9x}{9} = \frac{-9}{9}$

$\boxed {x = -1}$

Therefore, the value of $x$ is $-1$ .

5 0

3 years ago

Sarah said that 0.00001 is bigger than 0.001 because the first number has more digits to the right of the decimal point. Is Sara

Ivanshal [37]

No, she is wrong. 0.00001 has 4 zeros in front of the one and behind the decimal, making it 1/100000 or 1/10^5. For 0.001, there are 2 zeros in front, making it 1/1000 or 1/10^3. Since a number gets smaller as the denominator gets larger, and 10^5>10^3, 1/10^5<1/10^3

6 0

3 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

Hence the projection of b unto a is expressed as $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

7 0

3 years ago

Can someone pleaseeee help and if you’re correct i’ll give brainliest

matrenka [14]

The answer is the
The shape has 6 equal Square face
Because each side had 6

That on of the answer the next the shape has 6 vertices

Also the shape is soild

4 0

3 years ago