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Paraphin [41]
3 years ago
7

Erica had 6 coins in her coin collection. She goes to a coin show and buys some more coins. How many does she have now?

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0

Why would she be paying for another form of currency is the real question?

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What is y = 1/3x + 8 2/3 in point-slope form?
TiliK225 [7]

Answer:

y= 1/3x+26/3

Step-by-step explanation:

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4 0
3 years ago
Small library contains 700 novels. how many ways can You check out three novels
schepotkina [342]

The first book you select can be any one of 700.

. . . For each of those ...

The second book can be any one of the other 699.

. . . For each of those ...

The third book can be any one of the remining 698.

The total number of ways to gather three books from the shelves into your hands is  (700 · 699 · 698)  =  <em>341,531,400 ways</em> .

<em>BUT ...</em>

When you bring three books to the check-out counter, Marian the Librarian doesn't know in which order you took them down off the shelves.  You could have gathered the same three books in (3 · 2 · 1) = 6 different ways.

So, even though there are 341,531,400 ways to<em> </em>gather up three books, there are only (341,531,400 / 6) = 56,921,900 different GROUPS of three books that you can choose to take home.

8 0
3 years ago
The equation Y equals 4/10 X describes the number of kilometers y that a van travels in x minutes. What is the constant speed of
Mekhanik [1.2K]

Answer:

\frac{4}{10}=0.4 kilometers per hour.

Step-by-step explanation:

We have been given an y=\frac{4}{10}x, which describes the number of kilometers y that a van travels in x minutes. We are asked to to find the constant speed of the van in terms of hours.

We can see that van travel \frac{4}{10}x kilometers in x hours. To find the constant speed of van, we will substitute x=1 in our given equation as:

y=\frac{4}{10}(1)

y=\frac{4}{10}

Since van travels \frac{4}{10} kilometers in one hour, therefore, constant speed of van is \frac{4}{10} kilometer per hour or 0.4 kilometers per hour.

3 0
3 years ago
Help solving this problem, the second problem not the third
yawa3891 [41]

Given:

1 Van and 4 buses filled with 195 students.

1 Van and 5 buses filled with 241 students.

Let x and y be the number of students in Van and number of students in bus.

\begin{gathered} x+4y=195\ldots\text{ (1)} \\ x+5y=241\ldots\text{ (2)} \end{gathered}

Subtract equation (1) from equation (2)

\begin{gathered} x+5y-x-4y=241-195 \\ y=46 \end{gathered}

Substitute y=46 in equation (1)

\begin{gathered} x+4(46)=195 \\ x+184=195 \\ x=195-184 \\ x=11 \end{gathered}

Number of students that van can carry is 11.

Number of students that bus can carry is 46

7 0
1 year ago
Someone please help me with this math question
Molodets [167]

Answer:

3rd one

Step-by-step explanation:

5 0
3 years ago
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