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3 years ago

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Triangle ABC with A at 0 comma 0, B at 2 comma 4 and C at 0 comma 2, the measure of angle C is 127 degrees, and the measure of a

ngle A is 40 degrees, triangle DEF with D at 2 comma 0, E at 4 comma 4 and F at 4 comma 2, the measure of angle F is 127 degrees, and the measure of angle E is 40 degrees
Name the congruent triangles and justify the reason for congruence.

ΔABC ≅ ΔFDE by HL
ΔABC ≅ ΔEDF by ASA
ΔABC ≅ ΔFED by HL
ΔABC ≅ ΔFED by ASA

1 answer:

Nikolay [14]3 years ago

6 0

Answer:

The Answer is B.

Step-by-step explanation:

I got it right on my test

For further evidence here is a picture of the answer

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What is the value of the 30th percentile for the data set? 6283 5700 6381 6274 5700 5896 5972 6075 5993 5581 5972 6274 6075 5896

Alex17521 [72]

<h2>Answer:</h2>

5896

<h2>Step-by-step explanation:</h2>

Given data set:

6283 5700 6381 6274 5700 5896 5972 6075 5993 5581 5972 6274 6075 5896

To calculate the 30th percentile;

<em>i. Rearrange the given data set in ascending order.</em>

5581 5700 5700 5896 5896 5972 5972 5993 6075 6075 6274 6274 6283 6381

<em>ii. Use the following formula to get the index of the value at the 30th percentile.</em>

N = p(n)

<em>Where;</em>

N = the number of data points at or below the intended percentile.

p = the intended percentile.

n = the number of points in the data.

<em>In this case;</em>

p = 30 percent = 0.3

n = 14

<em>Substitute these values into the equation;</em>

N = 0.3(14)

N = 4.2

<em>iii. From the calculated index, find the value of the 30th percentile.</em>

If the index is a whole number x, the desired percentile is the average of the values at index x and x+1.

For example if the index is 4, then the desired percentile is the average of the values at index 4 and 5. In our case, that will be;

$\frac{5896+5896}{2}$ = 5896

If the index is a decimal number, it is rounded up to the nearest integer. The value at the rounded index is the desired percentile.

For example, in our case, the index is 4.2 which when rounded up becomes 4.

Therefore, the data point or value at index 4 is the 30th percentile. From the arrangement in (ii) above, that will be 5896. i.e

5581 5700 5700 <u>5896</u> 5896 5972 5972 5993 6075 6075 6274 6274 6283 6381

8 0

3 years ago

Can someone explain and answer please??

Nat2105 [25]

Simplify the ration expression
$\frac{3x-6}{x-2}$

start by seeing if anything in the numerator or denominator can be factored,
you should notice that you can factor out a 3 from 3x-6 in the numerator

when you do so, the result is
$\frac{3 *(x-2)}{x-2}$

now, since there is an x-2 in the numerator and denominator, they "cancel" out since

$\frac{x-2}{x-2} =1$
however, only when $x \neq 2$
since $\frac{0}{0} \neq 1$

when you cancel out the x-2, you're left with 3

hence, your answer is C

8 0

3 years ago

Please help with all three will give brainliest and $5

Dafna1 [17]

$\frac{x}{y}$ Answer:

Six would be your answer

Step-by-step explanation:

2y-9= y-2

-y -Y

y-9=-2

y=-2+9

y=6

7 0

3 years ago

g A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a

Helga [31]

Answer:

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.02})^{2}$

$n = 2401$

The sample size needed is 2401.

7 0

3 years ago

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In order to keep a boat from drifting away, the boat is tied to a pier with a 60-foot rope. When the boat drifts as far from the

Rus_ich [418]

The answer is C) hope this helped!

6 0

3 years ago